Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
Answer:
its 45
Step-by-step explanation:
Answer: 495 bacteria in 2 minutes.
Step-by-step explanation:
We would apply the formula,
y = ab^t
Where
a represents the initial amount of bacteria.
t represents the doubling time.
From the information given
a = 10
t = 15 seconds
Since after 15 seconds, the amount of bacteria multiplies by 2, then
y = 2 × 10 = 20
Therefore
20 = 10 × b^15
Dividing through by 10, it becomes
2 = b^15
Raising both sides of the equation by 1/15, it becomes
2^(1/15) = b^15/15
b = 1.047
The equation becomes
y = 10(1.047)^t
For t = 2 minutes(2 × 60 = 120 seconds), then
y = 10(1.047)^120
y = 495 bacteria
Answer:
f ( x ) does not satisfy the mean value theorem
Step-by-step explanation:
The given data :-
- f(x) = 3x - 4 cos ( 2x + 1 )
- f'(x) = 3 +8 sin ( 2x + 1 )
- The interval [ -1 , 2 ]
Solution :-
i) f(x) is continuous on [ -1 , 2 ]
ii) f(x) is derivable on ( -1 , 2 )
f ( -1 ) = 3 * (-1 ) - 4 cos [ 2 * ( -1 ) + 1 ] = - 3 + cos (-1 ) = - 3 - 4 * 0.9998 = - 6.992
f ( 2 ) = 3 * 2 - 4 cos ( 4 * 2 + 1 ) = 6 + 4 cos 9 = 6 - 3.9507 = - 3.04924
iii) f ( -1 ) ≠ f ( 2 )
f ( x ) is not real valued function so it does not satisfy the mean value theorem
