Answer:
Step-by-step explanation:
Quadratic formula: 
when the equation is 
The given equation is 
. Let's first arrange this so its format looks like 
:
Subtract 1 from both sides of the equation
Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:
I hope this helps!
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Answer:
9am why did you ask?
Step-by-step explanation:
btw ty for the points
They're irrational numbers, so they can't be exactly written down.
Rounded to the nearest thousandth, they are
- 15.280
and
- 0.720 .
