Answer:
N = 35 × 34^6
N = 54,068,154,560
Step-by-step explanation:
Given;
The license plate have 7 characters.
Each character can be a capital letter, or a digit except for 0.
There are 26 capital letters
And there are 9 digits excluding 0
The total number of possible entries in each character is;
26+9 = 35
The number of license plates in which no two adjacent characters are the same are;
For no two adjacent characters of the license plate not to be the same that is no two characters that follow each other can be the same, the number of possible entries in the adjacent characters apart from the first character would be reduced by one.
N = 35 × 34 ×34×34×34×34×34
N = 35 × 34^6
N = 54,068,154,560
Therefore, there are 54,068,154,560 possible license plates
0/9 would be the fraction
1. Divide 240 by 10 = 24
2. Multiply 24 • 8 = 192
<em>Michele </em><em>will </em><em>need </em><em><u>1</u></em><em><u>9</u></em><em><u>2</u></em><em><u> </u></em><em><u>oz.</u></em><em> </em><em>of </em><em>mayonnaise</em><em>.</em>
Answer:
a) Infinite solutions
b) No solutions
Step-by-step explanation:
First, know the following:
If the graphs intersect, there's only one solution.
If the graphs are parallel, there are no solutions.
If the graphs are the exact same line, there are infinite solutions.
For a):
Change the first equation into a linear one.
Change the second equation into a linear one.
- 4x+6y=12
- 6y=-4x+12

Boom. You have two equations which are equal. As stated above, graphs on the exact same line have infinite solutions.
For b)
They are already in linear form so hurray.

These lines are parallel since they have the SAME slope but a different y-intercept. As stated above, parallel lines have no solutions.
Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
