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Slav-nsk [51]
3 years ago
8

Find the missing number to make these fractions equal. 2/8 = ?/4

Mathematics
2 answers:
ioda3 years ago
6 0

Answer:

?= 1

Step-by-step explanation:

Marta_Voda [28]3 years ago
3 0

Answer:

Step-by-step explanation:

let the missing number be x

2/8=x/4(do cross multiplication)

8*x=4*2

8x=8

x=8/8

x=1

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A city has a population of 380,000 people. Suppose that each year the population grows by 3.5%, What will the population be afte
Marizza181 [45]
I think it’d be 536,028 at the end of 10 years of growth. I hope this helped.
5 0
3 years ago
Can anyone help me please solving this maths problems not sure if. Thanks
Marrrta [24]
The reason you can only compare the numerators is because the denominators are the same- leaving little comparison to really make. The numerators will determine which fraction is greater or smaller.

Ex. 4/5 or 3/5

which is greater? Which is smaller?

It can be seen that the denominators are the same, now finally comparing the numerators will answer both questions.

please vote my answer brainliest. thanks!
5 0
3 years ago
Just a bunch of easy ones
Scilla [17]

Answer:

1. 5lb bag is cheaper

2. 6 mpm (minutes per miles)

3. Brycen

4. 18 mpm faster

5. 32 total shapes

6. 75

7. not enough info

8. 50 miles

9. 2

10. 2

Step-by-step explanation:

3lb=$3.54=1lb=$1.18

5lb=$5.85=1lb=$0.85

12 minutes/2 miles=6 mpm

24 minutes/1 mile=24 mpm

24-6=18 mpm faster

25% of 100= 4

4×8=32

60% of 80= 75

process of elimination:

24.5 is less than 35 so no

50×.7=35, total miles is 50

5 0
3 years ago
Read 2 more answers
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
How do you solve 4x-7x=13
Rufina [12.5K]


13=-3x

3x=-13

x=-13/3=-4 1/3

3 0
3 years ago
Read 2 more answers
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