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Mama L [17]
3 years ago
6

Solve (2x + y) (2x - y)

Mathematics
2 answers:
creativ13 [48]3 years ago
4 0

Answer:

Step-by-step explanation:

there is  formula (a+b)(a-b)=a^2-b^2

(2x+y)(2x-y)=(2x)^2-y^2=4x^2-y^2

Vaselesa [24]3 years ago
3 0

Answer:

Hello There!

~~~~~~~~~~~

(2x + y) (2x - y) =

4x^{2}  - y^{2}

Step-by-step explanation: Simplify the expression.

Hope this helped you. Brainliest would be nice!

☆_____________❤︎______________☆

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4<br>_ compared to 0.45 <br>9
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Step-by-step explanation:

\dfrac{4}{9}=0.\overline{4}

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3 years ago
When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

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Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

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For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

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8 0
2 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

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\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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