Answer:
The percentage of the data between 580 and 620 is 68.26 %
Step-by-step explanation:
Given,
Mean, = 600,
Standard deviation, = 20,
Using the equation,
Z-score for the data 580 =
While, the z-score for the data 620 =
Using normal distribution table,
P(580 < z) = 0.1587
Also, P(620 > z) = 0.8413
Hence, the percent of the data is between 580 and 620 = P(620 > z) - P(580 < z)
= 0.8413 - 0.1587
= 0.6826
= 68.26 %