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scoray [572]
3 years ago
13

PLSSSSSSSSSSS HEEEEEELP????The mean of a set of normally distributed data is 600 with a standard deviation of 20. What percent o

f the data is between 580 and 620?
Mathematics
2 answers:
grin007 [14]3 years ago
8 0

Answer:

The percentage of the data between 580 and 620 is 68.26 %

Step-by-step explanation:

Given,

Mean, \mu = 600,

Standard deviation, \sigma = 20,

Using the equation,

z-score=\frac{x-\mu}{\sigma}

Z-score for the data 580 = \frac{580-600}{20}

=\frac{-20}{20}

=-1

While, the z-score for the data 620 = \frac{620-600}{20}

=\frac{20}{20}

=1

Using normal distribution table,

P(580 < z) = 0.1587

Also, P(620 > z) = 0.8413

Hence, the percent of the data is between 580 and 620 = P(620 > z)  - P(580 < z)

= 0.8413  - 0.1587

= 0.6826

= 68.26 %

Ivanshal [37]3 years ago
6 0
Z = (X-Mean)/SD 
<span>z1 = (580-600)/20 = - 1 </span>
<span>z2 = (620-600)/20 = + 1 </span>
<span>According to the Empirical Rule 68-95-99.7 </span>
<span>Mean +/- 1*SD covers 68% of the values </span>
<span>Therefore, required percent is 68%
hopes this help :) :D :)</span>
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