(4,6) and 7 is the answer
E^2x -2e^x -8=0 => e<span>^(2x) -2e^x -8=0
Temporarily replace e^x with y.
Then (y)^2 - 2y - 8 = 0. Factors are (y-4) and (y+2).
Roots are y = 4 and y= -2.
Now remembering that we temporarily replaced e^x with y, we let
y=4 = e^x. We need to solve for x. Taking the natural log of both sides, we get:
ln 4 = x (answer)
We have to discard the other root (y= -2), because we cannot take the ln of a negative number.
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Answer:
The answer is that they are both paralleagrams.
Step-by-step explanation:
Hope this helps
Answer:
2nd option
Step-by-step explanation:
Given
2x - 8y + 3x² + 7y - 12x ← collect like terms
= 3x² + (2x - 12x) + (- 8y + 7y)
= 3x² + (- 10x) + (- y)
= 3x² - 10x - y
The numbers go up in a linear fashion (by 1)
So, positive linear association
