Equilateral triangle. because all sides are equal.
We can use a system of equations in order to solve for both of the numbers. Let's start off by assigning variables to each number. The bigger number can be 'x', and the smaller number can be 'y'.
We can make two equations from the given:
x = 18 + y
("One number is 18 more than another number")
x + y = 36
("The sum of the numbers is 36")
If you look at the first equation, the variable 'x' already has a value (18 + y). We can input its value into the second equation in order to solve for y:
x + y = 36
(18 + y) + y = 36
18 + 2y = 36
2y = 18
y = 9
Input the value of 'y' into the first equation:
x = 18 + y
x = 18 + 9
x = 27
<u>One number is 27 and the other number number is 9.</u>
<u></u>
Let me know if you'd like me to explain anything I did here.
- breezyツ
Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.
He rented maybe three game for twenty two dollars
The answer is (5.5,-6.5) because you find the midpoint for the x-axis which is 9+2 then divide by 2 then do the same for the y-axis and place them together.
