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tatyana61 [14]
3 years ago
9

ANSWER ASAP PLS!!!!!!

Mathematics
1 answer:
Darya [45]3 years ago
4 0

Answer: I imagine that the question was: "What is the wrong answer between these choices?" Therefore, it is the third choice.

Explanation:

2(m∠PQS) ≠ (m∠RQS)

2(47°) ≠ 47°

94° ≠ 47°

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umka21 [38]
Mean a=75/10, mean b=73/10............about the same

range a=2-10=8, range b=4-12=8.........about the same
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What is y=1/2x-3 on a graph
Anvisha [2.4K]
This needs a graph to solve
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4 years ago
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I need help with number 2 and three.
wolverine [178]

Answer:

I think it is acute because if the angle was over 90 degrees it would be and obtuse then

Step-by-step explanation: I hope this helps u out very much thank you :)

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3 years ago
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Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha
Nookie1986 [14]

Answer:

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.  The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

If we know that (3, -30), (-2, 0) and (18, 0) are part of the parabola, the following linear system of equations is formed:

9\cdot a +3\cdot b + c = -30

4\cdot a -2\cdot b +c = 0

324\cdot a +18\cdot b + c = 0

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

a = \frac{2}{5}, b = -\frac{32}{5}, c = -\frac{72}{5}.

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.

Now, we calculate the average rate of change (r), dimensionless, between x = -2 and x = 8 by using the formula of secant line slope:

r = \frac{y(8)-y(-2)}{8-(-2)}

r = \frac{y(8)-y(-2)}{10}

x = -2

y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}

y(-2) = 0

x = 8

y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}

y(8) = -40

r = \frac{-40-0}{10}

r = -4

The average rate of change of the parabola is -4.

3 0
3 years ago
Anyone know how to do this? will give brainlest! if you cant help, have a great day!!!
Aleks04 [339]
M= 2 :) I hope this helped you
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