Answer: y = 3/2x + 1
Step-by-step explanation: For a perpendicular line, take the reciprocal of "m" and reverse the sign.
- 2/3 becomes +3/2
Then substitute the y and x values of the given coordinate into the equation and solve for "b"
y = mx + b
-2 = 3/2(-2) + b
-2 = -3 + b
-2 +3 = b
+1 = b Substitute for b in y = (3/2)x + 1
Answer:
g(x) = - x² - 4 ⇒ A
Step-by-step explanation:
Let us revise the reflection and translation of a function
- If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
- If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)
- If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)
- If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)
- If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k
- If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) – k
f(x) = x² is the blue curve
g(x) is its image is the red curve
∵ g(x) is the image of f(x)
∵ f(x) is opened upward
∵ g(x) is opened downward
→ That means the sign of y-coordinates of all points on the blue
graph are opposite
∴ f(x) is reflected about the x-axis
∴ Its image is - f(x)
∵ The vertex of f(x) is (0, 0)
∵ The vertex of g(x) = (0, -4)
→ That means the function translated 4 units down
∴ - f(x) is translated 4 units down
∴ Its image is - f(x) - 4
∴ g(x) = - f(x) - 4
∵ f(x) = x²
∴ g(x) = - x² - 4
Hello from MrBillDoesMath!
Answer:
33769/181
Discussion:
Each term contains "x" so factoring it out gives
x( 1/4 + 1/14 + 1/17) = 71 (*)
Use common factor (17*14*4 = 952) as the denominator to combine terms:
1/4 = (17*14)/ 952 = 238/952
1/14 = (17*4)/952 = 68/952
1/17 = (14*4)/952 = 56/952
so 1/4 + 1/14 + 1/17 = (238 + 68 + 56)/ 952 = 362/952 = 181/476
Substituting in (*) gives
x ( 181/476) = 71 => multiply both sides by 476/181
x = (71 * 476)/181 => 71* 476 =33769
x = 33769/181
Thank you,
MrB
we know that
For the function shown on the graph
The domain is the interval--------> (-∞,0]

All real numbers less than or equal to zero
The range is the interval--------> [0,∞)

All real numbers greater than or equal to zero
so
Statements
<u>case A)</u> The range of the graph is all real numbers less than or equal to 
The statement is False
Because the range is all numbers greater than or equal to zero
<u>case B)</u> The domain of the graph is all real numbers less than or equal to 
The statement is True
See the procedure
<u>case C)</u> The domain and range of the graph are the same
The statement is False
Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero
<u>case D)</u> The range of the graph is all real numbers
The statement is False
Because the range is all numbers greater than or equal to zero
therefore
<u>the answer is</u>
The domain of the graph is all real numbers less than or equal to 
Answer:
Solution given:
Y=90°
∠X=73°.
∠ZWY=80°
and XW=80.
ZY=?
We know that
In right angled triangle ∆ XYZ
Tan 73=
3.27=
3.27×[xy]=yz
xw+wy=
wy=
-80...........(1)
again
In right angled triangle WYZ
Tan 80=
5.67×wy=yz
wy=
yz=5.67×wy............................................(2)
E<u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u>&</u><u>2</u>
=
-80
-
=80
5.67yz-3.27yz=80*5.67*3.27
2.4yz =1483.272
yz=
yz=618.03
:.y=618.03unit.<u>the length of ZY to the nearest 100</u><u>th</u><u> </u><u>is</u><u> </u><u>6</u><u>1</u><u>8</u><u>.</u>