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3 years ago

Is 4,5, or 6 the solution of the equation c + 8 = 13?

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

8 0

Answer:

Subsitute the number five where the c is at and solve it 5 + 8 = 13

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A ray of light passing from air through an equilateral glass prism undergoes minimum

Mama L [17]

Answer: 45° and speed of light in prism 2×10⁸m/s

Step-by-step explanation:

The minimum deviation of the equilateral glass prism will form 60° angle.

So angle of incidence = 3/4×60

= 3 ×15

= 45°

Minimum deviation = δmin

= 30

After finding the value of μ using prism law

μ = 1.41

Speed of light will be 2×10⁸m/s

Must click thanks and mark brainliest

5 0

3 years ago

X^2 + Y^2 +ax + 2y + 3 = 0 What number is this equation the equation of a circle?

Sav [38]

Answer:

Eq: (x+a/2)²+(y+1)²=(a²-8)/4

Center: O(-a/2, -1)

Radius: r=0.5×sqrt(a²-8)

Mandatory: a>2×sqrt(2)

Step-by-step explanation:

The circle with center in O(xo,yo) and radius r has the equation:

(x-xo)²+(y-yo)²=r²

We have:

x²+y²+ax+2y+3=0

But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4

And

y²+2y+3=y²+2y+1+2=(y+1)²+2

Replacing, we get:

(x+a/2)²-a²/4+(y+1)²+2=0

(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4

By visual inspection we note that:

- center of circle: O(-a/2, -1)

- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)

6 0

3 years ago

Let f and g be functions given by f(x)=x^3 and g(x)=x^2 lxl

adell [148]

I post an image instead.
Correction: g(3)=(3²)|3|=9(3)=27

4 0

3 years ago

Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c

pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes) Frequency Relative frequency

0 - 20 10 10 / 50 = 0.2

21 - 40 15 15 / 50 = 0.3

41 - 60 10 10 / 50 = 0.2

61 - 80 5 5 / 50 = 0.1

81 - 100 10 10 / 50 = 0.2

50 1

From the above example, it can be seen that :

two or more classes can have the same relative frequency
The relative frequency is found by dividing the class frequencies by the total number of observations.
The sum of the relative frequencies must be equal to one
The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0

3 years ago

A taxi driver had 43 fares to and from the airport last Monday. The price for a ride to the airport is $12, and the price for a

leva [86]

Answer:

(25,18) is the required solution.

Step-by-step explanation:

We are given the following in the question:

Let x be the number of trips to the airport and y represent the number of trips from the airport.

Total number of fares to and from the airport = 43

Thus, we can write the equation:

$x+y = 43$

Price for a ride to the airport = $12

Price for a ride from the airport = $10

Total amount collected by the driver = $480

Thus, we can write the equation:

$12x+10y=480$

Solving the two equations, we get,

$12x+12y-(12x+10y)=516-480\\\Rightarrow 2y =36\\\Rightarrow y = 18\\\Rightarrow x = 43-18=25$

Thus, the driver made 25 trips to the airport and 18 trips from the airport.

The solution can be represented as (25,18)

7 0

3 years ago