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3 years ago

15

What is the range of the following data set?

2 answers:

ryzh [129]3 years ago

7 0

The range is given by: largest number in the data set - smallest number in the data set.

In our case, the largest value is 9 and the smallest value is 6.9. Therefor:

Range = 9 - 6.9 = 2.1

Thus, you have correctly identified the answer as the second choice (2.1). It is easy to get confused with much larger data sets but always keep in mind that the range is simply the largest value minus the smallest value. This makes sense since 'range' refers to the spread in something, for example if you were testing your vocal range you would find the highest note you could sing and the lowest note - this is the same here, we are just finding the range of a data set instead.

m_a_m_a [10]3 years ago

4 0

Answer:

The correct answer is second option

2.1

Step-by-step explanation:

Points to remember

<u>Range of a data set</u>

The range of a data set means that, the difference between the highest and lowest value of the data set.

<u>To find the range of data set</u>

It is given that, a data set

7.7, 8.4, 9, 8, 6.9

Highest value = 9 and lowest value = 6.9

Range = Highest value - lowest value

= 9 - 6.9 = 2.1

Therefore the correct answer is second option

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Find the standard deviation. Round to the nearest tenth. 1, 2, 11, 8, 16, 16,20, 16, 18 OA. 6.5 O B. 6.9 O C. 1.5 ? D. 7.4

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Answer:

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Step-by-step explanation:

First we find the average $\bar{x}$ of the 9 data:

$\bar{x} =\frac{\sum_{x=1}^{n}x_{i}}{n}$

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The formula of the standard deviation $\sigma$ is:

$\sigma=\sqrt{\frac{\sum_{x=1}^{n}(x_{i}-\bar{x})^{2}}{n}}$

We replace the data and find the value of the standard deviation:

$\sigma=\sqrt{\frac{(1-12)^{2}+(2-12)^{2}+(11-12)^{2}+(8-12)^{2}+(16-12)^{2}+(16-12)^{2}+(20-12)^{2}+(16-12)^{2}+(18-12)^{2}}{9}}$

$\sigma=\sqrt{\frac{(-11)^{2}+(-10)^{2}+(-1)^{2}+(-4)^{2}+(4)^{2}+(4)^{2}+(8)^{2}+(4)^{2}+(6)^{2}}{9}}=6,54$

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