Answer:
when two inscribed angles in one circle both equal 75°, the two angles must intercept the same arc that measures 75°.
Step-by-step Explanation:
The relationship between an intercepted arc and an inscribed angle is given as:
the measure of the intercepted arc = twice the inscribed angle that intercepts it.
Also, by virtue of this, when two inscribed angles intercepts the same arc, both inscribed angles are said to be congruent. And the measure of both angles equal the measure of the arc they both intercept.
Therefore, if the measure of an arc, that is intercepted by 2 inscribed angles, is given as 75°, both inscribed angles equal 75° as well. Thus, each of the inscribed angles is half the measure of the intercepted arc.
Therefore, the statement that is true about inscribed angles is: "when two inscribed angles in one circle both equal 75°, the two angles must intercept the same arc that measures 75°."
Since one angle is 90° and other is 45° ...so by angle sum property the third angle is also 45° ..
There is a theorem which states equal angles in a triangle have their opposite sides equal...hence base is also 6 ...then by Pythagoras Theorem..... x=√72=6√2
4.76 rounded to one decimal place is 4.8
Look at the decimal place you want to round (the 7, since it is the one decimal place).
Then look at the next digit (the 6). If it is 5 or greater, round up. Otherwise, round down.
You round up the 7 up because 6 is 5 or greater.
So you get the answer 4.8
There is no mistake unless you change the thing to the thing
2(4-16)-30
8-32+30
then eyah hope this helps and hope i can get a brainly?
Answer:
Area of a regular decagon with a perimeter of 60 ft. = 277 squared ft
Step-by-step explanation:
Decagon has 10 sides So 60/10 = 6 (each side = 6ft )
The sum of the interior angles of a decagon is 1 440 degrees.
There are 10 equal isosceles triangles of base angles 72 degrees in a decagon
Each isosceles triangle can subdivided into 2 right-angled triangles with height h and base length = (6/2) = 3 cm and base angle 72 degrees.
Height of right-angled triangle h = 3 tan 72 ft.
Area of 1 right-angled triangle = (1/2)(3)(3 tan 72) = 13.85 squared ft
Area of decagon = 20 right-angled triangles = 277 squared ft
