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3 years ago

How do you find the mean of a histogram?

Mathematics

1 answer:

Verizon [17]3 years ago

6 0

mean is the same as avrage

Step-by-step explanation:

Answer:In mathematics and statistics, the arithmetic mean, or simply the mean or average when the context is clear, is the sum of a collection of numbers divided by the number of numbers in the collection. The collection is often a set of results of an experiment, or a set of results from a survey.

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Evaluating Expressions

d1i1m1o1n [39]

Answer: 13. -12 , 14. 40 , 15. 16 , 16. 4.5

Step-by-step explanation:

8 0

2 years ago

Is this correct and if not which one is right

just olya [345]

Yes it's correct..........

3 0

3 years ago

Read 2 more answers

Find the area under the standard normal distribution curve for the following intervals. a. Between z = 0 and z = 2.0 b. To the r

vesna_86 [32]

Answer:

a) $P(0$

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

$P(0$

b) $P(Z>1.5) =1-P(Z$

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

$P(Z>1.5) =1-P(Z$

c) $P(z$

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

$P(z$

d) $P(-2.78$

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

$P(-2.78$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

We want this probability:

$P(0$

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

$P(0$

Part b

For this case we want this probability:

$P(Z>1.5)$

And we can use the complement rule and we have:

$P(Z>1.5) =1-P(Z$

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

$P(Z>1.5) =1-P(Z$

Part c

We want this probability:

$P(z$

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

$P(z$

Part d

We want this probability:

$P(-2.78$

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

$P(-2.78$

5 0

3 years ago

CAN YOU PLEASE HELPPPPP!!!!!!!!! PLSSS

ASHA 777 [7]

Answer:

y= -3/8x + 1

Step-by-step explanation:

-4 = x1

5 = y1

y-y1=m(x-x1)

y-5 = -3/8(x-(-4)

y-5 = -3/8x + -3/2

+5 +5

y= -3/8x + 1

3 0

2 years ago

Read 2 more answers

The manager of a restaurant found that the cost to produce 100 cups of coffee is $63.00, while the cost to produce 400 cups is

oksano4ka [1.4K]

Answer: a. y= 0.5x+13

b. 460 cups of coffee are produced if the cost of production is $243.00.

Step-by-step explanation:

Let x= Number of cups of coffee

y= cost of x cup

a. Let y =mx+c which is a linear equation

According to the question,

$63= 100m+c\ ...(i)$

$213=400m+c\ ...(ii)$

Subtract (i) from (ii), we get

$150=300m\\\\\Rightarrow\ m=\dfrac{150}{300}=0.5$

Put value of m in (i), we get

$63=100(0.5)+c\\\\\Rightarrow\ 63=50+c\\\\\Rightarrow c= 63-50=13$

Put value of m and c in the linear equation ,. we get y= 0.5x+13

b. Put y= 243

$243=0.5x+13\\\\\Rightarrow\ 243-13=0.5x\\\\\Rightarrow\ 230=0.5x\\\\\Rightarrow\ x=\dfrac{230}{0.5}=\dfrac{2300}{5}=460$

Hence, 460 cups of coffee are produced if the cost of production is $243.00.

6 0

3 years ago