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gizmo_the_mogwai [7]
3 years ago
11

More Challenges:

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

1. -m(-8n^2-7n+1)

2. (2w+7c) (v+7c)

5. (q+3r)(q^2-3qr+9r^2)

7. x= - 4/7,  1/9

See below for additional problems and help.

Step-by-step explanation:

To factor polynomials, look for patterns and greatest common factors. When you remove these factors, write the factor and what remains.

For example:

  1. 8mn^2+7mn-m\\-m(-8n^2-7n+1)

Notice the term (-8n^2-7n+1) is left and is the term when the expression is divided by -m.

     2. Factor by grouping is similar. Pull out factors within pairs of term. Separate the terms by parenthesis. If the quantities in the [parenthesis are the same, the factoring has been successful.

(2vw + 7cv) + (14cw + 49c^2)\\v(2w+7c)+7c(2w+7c)

Notice that (2w+7c) is the same. The factoring is complete. The factors are:

(2w+7c) (v+7c)

3 - 6 is similar using specific forms for factoring. To find the forms, look in your notes or at resources on online. Here is one example.

      4. A sum of cubes has the form

a^3 + b^3 = (a + b)(a^2 -ab + b^2).

To use this form, take the cube root of each term. a = q and b=3r.

The factors are (q+3)(q^2-3qr+9r^2)

7-9 all involve factoring and then solving. You solve by setting the factors equal to 0.

7. (7x+4)(9x-1) = 0

(7x+4) = 0                      (9x-1)=0

7x=-4                               9x = 1

x= - 4/7                             x = 1/9

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Answer:

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Step-by-step explanation:

Question 11

g(x)= 4 + \dfrac{8}{5}x

(a) Rename g(x) as y  

y = 4 + \dfrac{8}{5}x

(b) Solve for x :  

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(c) Multiply each side by ⅝

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(d) Switch x and y  

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(e) Rename y as the inverse function  

g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}

(f) Compare with your function

f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

 

Question 12

h(x)= x - 2

(a) Rename h(x) as y  

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(b) Solve for x:  

x = y + 2

(c) Switch x and y  

y  = x + 2

(e) Rename y as the inverse function  

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).

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