We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
7*(n+4) =8
Step-by-step explanation:
seven times the sum
7*(
of an number and 4
7*( n+4)
equal 8
7*(n+4) =8
Answer:
The number is -9.
Step-by-step explanation:
If we let the number be x we have the equation 6x + 7 = -47.
6x + 7 - 7 = -47 - 7
6x = -54
x = 054/6
x = -9.
8x -5+2 x
8x+2x-5 ( combine like terms)
answer:
10x-5 or -5+10x
Let find the least of common multiple = LCM it’s for the denominators.
Multiple of the numerator then the denominator to get the denominators
Don’t forget to to add the numerator but leave the denominators the same
