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SVEN [57.7K]
3 years ago
6

What is the height of a projectile in 4 seconds if its initial height is 125 ft and it has a velocity of 300 ft per second? 972

ft 1,069 ft 1,207 ft 1,345 ft
Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

B. 1069 feet

Step-by-step explanation:

d=v_ot+\dfrac{1}{2}at^2 \\\\d=(300)(4)+\dfrac{1}{2}(-32)(4)^2 \\\\d=1200-256=944

Adding the initial 125 feet to this, you get a total height of 1069 feet. Hope this helps!

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Answer:

see explanation

Step-by-step explanation:

(a)

The zeros are x = 1 and x = 5, thus the factors are (x - 1) and (x - 5)

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To find a substitute (0, 15), the coordinates of the y- intercept into the equation.

15 = a(0 - 1)(0 - 5) = a(- 1)(- 5) = 5a ( divide both sides by 5)

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Thus h = 1, k = 5, a = 3 and

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(b)

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Equation of axis of symmetry is x = 3

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Coordinates of  P = (3, - 12 )

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3 years ago
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Answer:

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