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SVEN [57.7K]
3 years ago
6

What is the height of a projectile in 4 seconds if its initial height is 125 ft and it has a velocity of 300 ft per second? 972

ft 1,069 ft 1,207 ft 1,345 ft
Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

B. 1069 feet

Step-by-step explanation:

d=v_ot+\dfrac{1}{2}at^2 \\\\d=(300)(4)+\dfrac{1}{2}(-32)(4)^2 \\\\d=1200-256=944

Adding the initial 125 feet to this, you get a total height of 1069 feet. Hope this helps!

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PLZ HELP
nasty-shy [4]

Answer:

do u need other coordinates?

if so B'(1,-1)

C'(1,4)

D'(5,6)

the formula is (-x,y)

hope it helps :)

7 0
3 years ago
A cone is filled to a height of 3 inches with a liquid. The liquid is then poured into an empty cylinder with the same height an
Tasya [4]
Answer: 1 inch

Volume of the cylinder = πr²h

Volume of the cone = 1/3πr²h

If the radius are the same for both the cone and the cylinder, then the liquid will reach 1/3 of its height in the cylinder compared to the cone. 

Height = 1/3 x 3 inches 
Height = 1 inch

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Answer: The height of the cylinder will be 1 inch.
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3 0
3 years ago
What is the solution to the liner equation <br><br> -12+3b-1=-5-b
Natalija [7]

Answer:

b=2

Step-by-step explanation:

-12+3b-1=-5-b

Combine like terms

-13 +3b = -5-b

Add b to each side

-13+3b+b = -5-b+b

-13+4b = -5

Add 13 to each side

-13+13 +4b = -5+13

4b = 8

Divide by 4

4b/4 = 8/4

b = 2

6 0
3 years ago
Read 2 more answers
A bicyclist travels at a constant speed of 18 mi/h. How long does it take the bicyclist to travel 90 mi
Stells [14]
If the bicyclists is traveling 18 miles every hour and needs to travel a sum of 90 miles, you need to divide 90/18 equaling the total time (in hours) needed to travel 90 miles. Hope this helps
6 0
3 years ago
Read 2 more answers
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
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