Question

What is the height of a projectile in 4 seconds if its initial height is 125 ft and it has a velocity of 300 ft per second? 972 ft 1,069 ft 1,207 ft 1,345 ft

Answer 1

Answer:

B. 1069 feet

Step-by-step explanation:

$d=v_ot+\dfrac{1}{2}at^2 \\\\d=(300)(4)+\dfrac{1}{2}(-32)(4)^2 \\\\d=1200-256=944$

Adding the initial 125 feet to this, you get a total height of 1069 feet. Hope this helps!