1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex17521 [72]
4 years ago
10

An opinion poll asks a simple random sample of 100 college seniors how they view their job prospects. In all, 53 say "good." Doe

s the poll give convincing evidence to conclude that more than half of all seniors think their job prospects are good? If p = the proportion of all college seniors who say their job prospects are good, what are the the hypotheses for a test to answer this question?
Mathematics
1 answer:
ValentinkaMS [17]4 years ago
7 0

Answer:

We are tryng to proof if more than half of all seniors think their job prospects are good so that would be the alternative hypothesis and the complement rule would be the null hypothesis.:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

Step-by-step explanation:

Information provided

n=100 represent the random sample ofcollege senior selected

X=53 represent the college seniors who say good

\hat p=\frac{53}{100}=0.53 estimated proportion of seniors who think their job prospects are good

p_o=0.5 is the value that we want to test

z would represent the statistic

p_v represent the p value

System of hypothesis

We are tryng to proof if more than half of all seniors think their job prospects are good so that would be the alternative hypothesis and the complement rule would be the null hypothesis.:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we have:

z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=0.6  

The p value for this case would be given by

p_v =P(z>0.6)=0.274  

You might be interested in
What is x in this problem 12 x 4x
Airida [17]

12 x 4x

-12

4x=-12

x= -3

3 0
3 years ago
Read 2 more answers
I am putting a lot of points on the line! Please help!!!!!!!!!
zvonat [6]

Answer:

s > 118 2/3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
There are 93 calories in a small candy bar how many calories are ther in a half dozen small candy bars?
Tju [1.3M]
Half dozen = 6

6 × 93 = 558

Your answer is 558
6 0
4 years ago
Read 2 more answers
How is the graph of y= 1/3x related to its parent function y=1/x
V125BC [204]

B it is horizontally stretched by a factor of of 3 and reflected over the y

7 0
3 years ago
Read 2 more answers
A restaurant chef made 2 2/3 jars of pasta sauce. Each serving of pasta requires 1/3 of a jar of sauce. How many servings of pas
stepladder [879]

Answer:

<h2>8 Servings</h2>

Step-by-step explanation:

So let's solve this

1/3 (1)

2/3 (2)

3/3 or 1 (3)

4/3 or 1 1/3 (4)

5/3 or 1 2/3 (5)

6/3 or 2 (6)

7/3 or 2 1/3 (7)

8/3 or 2 2/3 (8)

8 servings of pasta are possible with 2 2/3 jars of sauce.

I'm always happy to help :)

6 0
3 years ago
Other questions:
  • Please help on this one?
    6·1 answer
  • Planet Company had operating income of $12,000, average operating assets of $125,000, and sales of $45,000. What is Planet's ret
    14·1 answer
  • 4(2 + 6v) You don't have to work t out if you don't want to.
    9·1 answer
  • Help with both please
    11·1 answer
  • Help me plzzzz!!!!! I need help 5-11
    10·1 answer
  • Greg studied for 12 minutes. This is 40% of the time he wants to study today. How many more minutes does Greg need to study toda
    7·1 answer
  • HELP MEH PLZ!!
    9·1 answer
  • The equation y=1/9x represents the distance y, kilometers, that Patrick traveled in x minutes while training for the cycling por
    14·1 answer
  • A weightlifter's maximum amount he can lift is 300 pounds. Write and solve an equality to find the number of 50 pound weights he
    13·1 answer
  • PLS HELP ME 50 POINTS AND I WILL MARK THE BRAINLIEST
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!