This question was not written correctly
Complete Question
NEWSPAPERS Tamika delivered 50² newspapers last summer. Write 50² as a product of the same factor. Then find the value.
Answer:
The value is 2500
Step-by-step explanation:
We are told in the above question that:
Tamika delivered 50² newspapers last summer.
Writing 50² as a product is given as:
50 × 50
Hence, the value of 50 × 50
= 2500.
Therefore, the value is 2500
Answer:
Step-by-step explanation:
What you gave 4x – y = 7 is in standard form
The problem on screen
4x-2/3y=7
The standard form is 12x-2y=21
Answer is A
Answer:
- 5(x +1.5)^2
- 10(x +1)^2
- 1/4(x +2)^2
- 3(x +5/6)^2
Step-by-step explanation:
When your desired form is expanded, it becomes ...
a(x +b)^2 = a(x^2 +2bx +b^2) = ax^2 +2abx +ab^2
This tells you the overall factor (a) is the leading coefficient of the given trinomial. Factoring that out, you can find b as the root of the remaining constant.
a) 5x^2 +15x +11.25 = 5(x^2 +3x +2.25) = 5(x +1.5)^2
b) 10x^2 +20x +10 = 10(x^2 +2x +1) = 10(x +1)^2
c) 1/4x^2 +x +1 = 1/4(x^2 +4x +4) = 1/4(x +2)^2
d) 3x^2 +5x +25/12 = 3(x^2 +5/3x +25/36) = 3(x +5/6)^2
_____
<em>Additional comment</em>
If you know beforehand that the expressions can be factored this way, finding the two constants (a, b) is an almost trivial exercise. It gets trickier when you're trying to write a general expression in vertex form (this form with an added constant). For that, you must develop the value of b from the coefficient of the linear term inside parentheses.
A) The possible three-course selections are as shown below.
B) The likelihood of selecting the combinations is 0.1 since there are 10 combinations in total.
<h3>How to solve probability combinations?</h3>
A combination operator can be used when we need to find the number of ways to select "k" items from a set of "n" items. It is also called a 'choose' operator where it is read as 'n choose k' and is represented and calculated as given below
From the choices given, there are 5 courses which are given below:
EPR 605
EPR 643
EPR 648
EPR 674
EPR 681
We need to find the combinations of 3 of these given 5 courses, which are given below (omitting the course code, EPR):
605-643-648
605-643-674
605-643-681
605-648-674
605-648-681
605-674-681
643-648-674
643-648-681
643-674-681
648-674-681
10 of the given choices of combinations are possible since they do not include a repeated course number.
The likelihood of selecting the combination of EPR 681, EPR 648, and EPR 605 is 0.1 since there are 10 combinations in total.
Complete question is;
A student entering a doctoral program in educational psychology is required to select three courses from the list of courses provided as part of his or her program. List all possible three-course selections. Comment on the likelihood that EPR 681, EPR 648, and EPR 605 will be selected. Select all the possible three-course selections below.
A. 648, 674, 605
B. 681, 648, 605
C. 681, 674, 605
D. 681, 681, 648
E. 674, 643, 674
F. 674, 605, 643
G. 681, 648, 674
H. 681, 681
I. 681, 648, 643
J. 648, 605, 643
K. 648, 674, 643
L. 681, 605, 643
M. 643, 694, 643
N. 681, 674, 643
Read more about Probability Combinations at; brainly.com/question/3901018
#SPJ1
Answer:
Domain: All Real Numbers
Range: y<0
Step-by-step explanation:
Looking at the graph, you can tell that the variable y has a lower point.
( I'm not sure how accurate this is I'm doing the same test right now. ;-;)
