Alright,
directix is y=something so it opens down or up
we use
(x-h)²=4p(y-k)
the vertex is (h,k)
and p is distance from focus to vertex
if focus is above directix, p is positive
if focus is below directix, p is negative
so we gts
focus=(1,1)
directix is y=-1
1>-1
focus is above
oh, vertex is in middle of focus and directix
so
beteeen (1,1) and y=-1 is, hmm
that is a distance of 2 vertically
2/2=1
1 down from (1,1) is (1,0)
vertex is (1,0)
p=1
so
(x-1)²=4(1)(y-0)
solving for y to get into f(x)=something form
(x-1)²=4y
y=1/4(x-1)²
f(x)=1/4(x-1)²
4th option
Answer:
A. Negative information is given a relatively larger weight than positive information.
Step-by-step explanation:
Among the options enlisted, the fact that negative information is given a relatively larger weight than positive information, signposts the manner in which information is processed by an interviewer.
During the recruitment and/or interview processes, the recruiter is presented with a pool of candidates with varying skills and competencies. The scenario here will be that the recruiter will come up with penciled skills and character to;
1. Streamline and reduce the large number of applicants
2. Ensures that applicants are properly matched with the right jobs
To achieve the foregoing therefore, and considering the large pool of candidates, the interviewer will be highly sensitive to negative information that could pose a threat to the underlying recruitment objective.
Answer:
Part A: $60
Part B: $54
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
x = 2
y = 0
plug in values
- 0(2-0)-1
4- 0(2)-1
4-0-1
4-1
3
x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
