Answer:
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Step-by-step explanation:
Vertical lines never have a defined slope as you can never divide a number by zero
Answer: <em>3. The correct option is: A) 3.57 decibels.</em>
<em>6. The correct option is: B)
</em>
Step-by-step explanation:
3. Sound intensity is cut to 44% of its original level. That means, if the original sound intensity was 100, then now sound intensity will be 44.
So,
and 
Using the formula
, we will get.....

<em>(Rounded to the nearest hundredth)</em>
So, the loudness would be reduced by 3.57 decibels.
6. Given expression is: 
First applying the property
, we will get.....

Now using the formula,
, we will get....

Thus, the answer as a single natural logarithm is 
Answer:
162.9
Step-by-step explanation:
10 to the first power is 10 and 10 x 16.29=162.9
Answer:
f(g(x)) = 4x² + 16x + 13
Step-by-step explanation:
Given the composition of functions f(g(x)), for which f(x) = 4x + 5, and g(x) = x² + 4x + 2.
<h3><u>Definitions:</u></h3>
- The <u>polynomial in standard form</u> has terms that are arranged by <em>descending</em> order of degree.
- In the <u>composition of function</u><em> f </em>with function <em>g</em><em>, </em>which is alternatively expressed as <em>f </em>° <em>g,</em> is defined as (<em>f </em> ° <em>g</em>)(x) = f(g(x)).
In evaluating composition of functions, the first step is to evaluate the inner function, g(x). Then, we must use the derived value from g(x) as an input into f(x).
<h3><u>Solution:</u></h3>
Since we are not provided with any input values to evaluate the given composition of functions, we can express the given functions as follows:
f(x) = 4x + 5
g(x) = x² + 4x + 2
f(g(x)) = 4(x² + 4x + 2) + 5
Next, distribute 4 into the parenthesis:
f(g(x)) = 4x² + 16x + 8 + 5
Combine constants:
f(g(x)) = 4x² + 16x + 13
Therefore, f(g(x)) as a polynomial in <em>x</em> that is written in standard form is: 4x² + 16x + 13.
We have a circle of radius 5 m inside a square of side 10 m. The shaded area is:

Now, we calculate the area of the square and the circle:

Finally, the shaded area is: