Manny made 4 pizzas to share among himself and 6 friends. How much pizza will each person get? please awser in a fraction

Christine must buy at least $45$ fluid ounces of milk at the store. The store only sells milk in $200$ milliliter bottles. If th

amm1812

Answer:

7 bottles

Step-by-step explanation:

Christie needs to buy at least 45 fluid ounces of milk at the store.

33.8 fluid ounces=1 Liter

1 fluid ounce = $\dfrac{1}{33.8}$ Liters

45 fluid ounces = $\dfrac{1}{33.8} \times 45 =1.3313$ Liters$

Now:

1 Liter =1000 Milliliter

Therefore:

1.3313 Liter= 1000 X 1.3313 Milliliters

1.3313 Liter= 1331.3 Milliliter

Therefore, the smallest number of 200 milliliter bottles Christie must buy is:

$=\dfrac{1331.3}{200}=6.7 \\\approx 7$ bottles$

3 0

3 years ago

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Can anyone start me off on this? its trigonometric ratios

Alexxx [7]

Answer:

The angle is about 30.27 degrees.

Step-by-step explanation:

Use the trig ratio cosine because you are given the adjacent leg and the hypotenuse.

$cos^{-1} =19/22$

Plug into a calculator

Rounded to the nearest hundredth the angle is 30.27 degrees.

5 0

3 years ago

132% of 675?<br><br><br> Please help

kvasek [131]

Answer:

891

132 x 675

100

= 891

Step-by-step explanation:

7 0

3 years ago

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Help with problems 23-27

qaws [65]

25= 2/7 26= 1/9 27=2/3

5 0

3 years ago

A salesman for a new manufacturer of cellular phones claims not only that they cost the retailer less but also that the percenta

professor190 [17]

Answer:

$z=\frac{0.094-0.04}{\sqrt{0.0642(1-0.0642)(\frac{1}{180}+\frac{1}{225})}}=2.203$

$p_v =P(Z>2.203)= 0.0138$

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so then the claim from the retailer makes sense at 1% of significance.

Step-by-step explanation:

Use a significance level of α=0.01 for the test.

Data given and notation

$X_{1}=17$ represent the number of defectives from the retailer

$X_{2}=9$ represent the number of defectives from the competitor

$n_{1}=180$ sample 1 selected

$n_{2}=225$ sample 2 selected

$p_{1}=\frac{17}{180}=0.094$ represent the proportion estimated for defectives from the retailer

$p_{2}=\frac{9}{225}=0.04$ represent the proportion estimated for defectives from the competitor

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.01$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percentage of defective cellular phones found among his products, ( p1), will be no higher than the percentage of defectives found in a competitor's line, ( p2), the system of hypothesis would be:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{17+9}{180+225}=0.0642$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.094-0.04}{\sqrt{0.0642(1-0.0642)(\frac{1}{180}+\frac{1}{225})}}=2.203$

Statistical decision

Since is a right sided test the p value would be:

$p_v =P(Z>2.203)= 0.0138$

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so then the claim from the retailer makes sense at 1% of significance.

5 0

3 years ago