Easy there on the caps, partner.
The nine, using the distributive property, distributes itself across the brackets, and so 9 times t is 9t and 9 times -1 is -9.
Therefore, 9(t-1) = 9t -9
Answer:
Step-by-step explanation:
(B^2)(B^4) = B^(2+4)= B^6
answer is B
Answer: 4 cakes left in all.
Step-by-step explanation:
Given: Cakes left on first day= ![2\frac{3}{4}=\frac{11}{4}](https://tex.z-dn.net/?f=2%5Cfrac%7B3%7D%7B4%7D%3D%5Cfrac%7B11%7D%7B4%7D)
Cakes left on second day =![1\frac{1}{4}=\frac{5}{4}](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B5%7D%7B4%7D)
The number of cakes left in all=![\frac{11}{4}+\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B4%7D%2B%5Cfrac%7B5%7D%7B4%7D)
⇒The number of cakes left in all=![\frac{11+5}{4}=\frac{16}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B11%2B5%7D%7B4%7D%3D%5Cfrac%7B16%7D%7B4%7D)
Therefore, The number of cakes left in all=4
Answer:
<h2>12) There are 534 students who do not lunch in school.</h2>
Step-by-step explanation:
<h3>12. </h3><h3>Simple solution: </h3><h3>890 ÷ 5 = 178 </h3><h3>Therefore: 1/5 = 178 </h3><h3 /><h3>•To find the 2/5 of the students, we have to multiply 178 by 2</h3><h3>178 × 2 = 356</h3><h3>Therefore, 356 students stay to have lunch.</h3><h3 /><h3>•To find the remaining students who do not lunch in school, we have to subtract 356 to 890.</h3><h3>890 - 356 = 534</h3><h3>Therefore, there are 534 students who do not lunch in school.</h3><h3 /><h3 />