How do you solve this differential equation: 6y'+y*cosx=cosx
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The equation of the line is y = -x + 6 if the passes through the point (4, 2).
<h3>What is a straight line?</h3>A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
It is given that:
From the graph:
The slope of the line g = (0-5)/(-5-0)
= 1
The slope perpendicular to the line g:
= -1
y - 2 = -(x - 4)
y - 2 = -x + 4
y = -x + 6
Thus, the equation of the line is y = -x + 6 if the passes through the point (4, 2).
Learn more about the straight line here:
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