This function would have a maximum.
Since we are subtracting by a -4 for each increase in x, we know that the numbers will continue to go down. Given this fact, we know the number will never be higher than when we started, but the number could go infinitely low. As a result we have a maximum and no minimum.
Answer:
maybe rhombus
Step-by-step explanation:
don't take my word for it
Answer:
Step-by-step explanation:
from the graph of f(x)
when x=1,f(x)=0
or f(1)=0
when f(x)=2,x=2
for g(x)
when x=6,g(x)=16
or g(6)=16
when g(x)=18,x=32
for h(x)
when x=14
h(x)=27x-7
h(14)=27×14-7=7(27×2-1)=7(54-1)=7×53=371
h(x)=-493
27x-7=-493
27 x=-493+7=-486
3 x=-54
x=-18
for p(t)
when t=94
p(t)=24
p(94)=24
p(t)=67
t=31
, 
.