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Andrei [34K]
4 years ago
15

Find the product. Identify the two whole numbers between which the product lies: 5x7/10 (fraction)

Mathematics
1 answer:
uranmaximum [27]4 years ago
6 0
5/1 x 7/10 = 35/10 = 3 5/10 = 3 1/2 
3 and 4
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How do you do simultaneous equations ??
Pachacha [2.7K]
5x + 2y = 22
10x + 9y = 59
so now we need to either eliminate the y or the x and we need to multiply both numbers by something so that they will be the same and we can add or minus them.
so here I will eliminate x because it's easier

we multiply the top equation by 2 and the bottom equation by 1 and we get

10x + 4y = 44
10x + 9y = 59

so now we can see that the number of x's are the same and we can just find the DIFFERENCE between the two equations if it was -10x and 10x we would ADD

= 5y = 15
notice that the x'a have cancelled each other out

now we divide both sides by 5 so
y=3

now we have y, we need to substitute it into one of the original equations, doesn't matter which one. I'm going to do the first one.

5x + 2y = 22
5x + 2(3)=22
5x + 6 = 22
now minus 6 from both sides
5x = 16
divide both sides by 5
x = 3.2

we have our answers but to be sure we need to just substitute the values for x and y into BOTH original equations.

5x + 2y = 22
= 16 + 6 = 22

10x + 9y = 59
= 32 + 27 =59

Tadaa!! and there you have it
y = 3
x = 3.2

hope this helped :)
3 0
4 years ago
Read 2 more answers
Both circle A and circle B have a central angle measuring 135°. The ratio of the radius of circle A to the radius of circle B is
Darina [25.2K]
7/8π

The circles have the same central angle measures; therefore, the ratio of the intercepted arcs is the same as the ratio of the radii.

4/7 = 1/2π over x

x = 7/8π
3 0
4 years ago
Read 2 more answers
The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

\dfrac{\sqrt{3}}{4} \times a^{2}

Where <em>a </em>is the side of \triangle.

Area of hexagon = 6 \times \dfrac{\sqrt{3}}{4}\times a^{2}

We are given that area of hexagon = 169.74 ft^{2}

Let <em>s </em>be the side of hexagon.

\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = 6 \times side

Perimeter = 6 \times 8.08

\Rightarrow 48.5 ft

So, perimeter of given regular hexagon is 48.5 ft.

6 0
3 years ago
A and B are the subsets of a universal set U. If U = {1,2,3,4,5,6,7,8,9,10} A={1,2,3,5,7,9} and B ={1,2,3,6}, show that AUB comp
lisabon 2012 [21]

Answer:

AUB= {1,2,3,5,6,7,9}

AnB={1,2,3}

5 0
3 years ago
G(t) = (t-10) (t+1)<br> 1) What are the zeros of the function?
aniked [119]

Step-by-step explanation:

Write properties of function:

x intercept/zero: ; T1= -1 and T2=10

vertex form: g(t)=  (t-9/2)^2, (-121/4)

vertex: 9/2, 121/4

Explanation Write properties of function: Write properties of function:

x intercept/zero: ; t1=-1, and t2=10

vertex form: (t-9/2)^2, (-121/4)

vertex: 9/2, 121/4

hope this helped

4 0
3 years ago
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