5x + 2y = 22
10x + 9y = 59
so now we need to either eliminate the y or the x and we need to multiply both numbers by something so that they will be the same and we can add or minus them.
so here I will eliminate x because it's easier
we multiply the top equation by 2 and the bottom equation by 1 and we get
10x + 4y = 44
10x + 9y = 59
so now we can see that the number of x's are the same and we can just find the DIFFERENCE between the two equations if it was -10x and 10x we would ADD
= 5y = 15
notice that the x'a have cancelled each other out
now we divide both sides by 5 so
y=3
now we have y, we need to substitute it into one of the original equations, doesn't matter which one. I'm going to do the first one.
5x + 2y = 22
5x + 2(3)=22
5x + 6 = 22
now minus 6 from both sides
5x = 16
divide both sides by 5
x = 3.2
we have our answers but to be sure we need to just substitute the values for x and y into BOTH original equations.
5x + 2y = 22
= 16 + 6 = 22
10x + 9y = 59
= 32 + 27 =59
Tadaa!! and there you have it
y = 3
x = 3.2
hope this helped :)
7/8π
The circles have the same central angle measures; therefore, the ratio of the intercepted arcs is the same as the ratio of the radii.
4/7 = 1/2π over x
x = 7/8π
Answer:
Perimeter of given regular hexagon is <em>48.5 ft</em>.
Step-by-step explanation:
Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.
<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.
As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.
In other words,
are equilateral 
.
Area of an equilateral 
is defined as
:
Where <em>a </em>is the side of .
Area of hexagon = 
We are given that area of hexagon = 169.74 
Let <em>s </em>be the side of hexagon.
A regular Hexagon is made up of 6 equal sides, so
Perimeter of a regular hexagon = 
Perimeter = 
So, perimeter of given regular hexagon is 
.
Step-by-step explanation:
Write properties of function:
x intercept/zero: ; T1= -1 and T2=10
vertex form: g(t)= (t-9/2)^2, (-121/4)
vertex: 9/2, 121/4
Explanation Write properties of function: Write properties of function:
x intercept/zero: ; t1=-1, and t2=10
vertex form: (t-9/2)^2, (-121/4)
vertex: 9/2, 121/4
hope this helped
