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Mashutka [201]
4 years ago
5

Newborn babies in the United States have a mean birth weight of 7.5 pounds and a standard deviation of 1.25 pounds. Assume the d

ata possesses a bell-shaped distribution.
A. What are the upper and lower limits of the interval that contains 95% of all newborns in the United States?

B. Does a newborn with a birth weight of 4.5 pounds fall within an interval which contains 95% of all newborn birth weights. Why or why not?
Mathematics
1 answer:
Aleks [24]4 years ago
6 0

Answer:

A.

Lower limit: 5 pounds

Upper limit: 10 pounds

B.

4.5 is more than two standard deviations from the mean, so it does not fall within an interval which contains 95% of all newborn birth weights.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 7.5

Standard deviation = 1.25

A. What are the upper and lower limits of the interval that contains 95% of all newborns in the United States?

By the Empirical Rule, within 2 standard deviations of the mean.

Lower limit: 7.5 - 2*1.25 = 5 pounds

Upper limit: 7.5 + 2*1.25 = 10 pounds

B. Does a newborn with a birth weight of 4.5 pounds fall within an interval which contains 95% of all newborn birth weights. Why or why not?

4.5 is more than two standard deviations from the mean, so it does not fall within an interval which contains 95% of all newborn birth weights.

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ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80.2, \sigma = 11

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63.7 - 80.2}{11}

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Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

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5 0
4 years ago
John wants to buy a new laptop computer the computer store sells laptops for $480 or 9 credit payments of $58 how much interest
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5 0
4 years ago
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morpeh [17]

Answer:

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Step-by-step explanation:

The common difference is 142  - 140 = 2 so we have

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a1 = 140 - 98 =  42.

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MrRa [10]
<span>"the square of the sum of a number and 4 is 36"
=
</span><span>(x + 4)^2 = 36


</span>
5 0
3 years ago
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What is the solution to the system of equations?
Yuri [45]

Answer:

No solution

Step-by-step explanation:

Note how "2x" shows up in both equations.  This suggests doing a substitution to solve the system.

Focus first on the first equation.  Solving 2x - y = 7 for 2x, we get:

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6 0
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