Answer: The approximate values that every player make are,
Tammy = grace = 5.43 baskets
Jenny = 16.30 Baskets
Alex = 11.43 Baskets
Joan = 1.43
Step-by-step explanation:
Let Grace made x baskets.
Then According to the question,
Jenny made baskets = 3x
Alexis made basket = x + 6
Joan made basket = x - 4
Tammy made baskets = x
Since, Altogether the five players made 40 baskets.
⇒ x+ 3x + x + 6 + x - 4 + x = 40
⇒ 7x + 2 = 40
⇒ 7x = 38
⇒ x = 38 / 7 = 5.42857142857 ≈ 5.43
Thus, Grace made baskets= Tammy made baskets = x = 5.43
Jenny made baskets = 3 × x = 16.2857142857 ≈ 16.30
Alexis made basket = x + 6 = 11.4285714286 ≈ 11.43
Joan made basket = x - 4 = 1.42857142857
≈ 1.43
Answer:
2827.5
Step-by-step explanation:
You have to divide 82 inches (distance) by the speed of the snail which is 0.029mph then you get the answer above.
The answer is the first choice!!
Answer:
6 socks
Step-by-step explanation:
What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.
There are 12 black socks and in total they are 24, therefore the probability of drawing 1 is:
12/24
and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:
11/23
the final probability is the multiplication of these events:
(12/24) * (11/23)
P = 0.24
Now, to know how many you should get, we multiply the probability by the total number of socks, that is:
0.24 * 24 = 5.76
So you must take out at least 6 socks for the above to happen.
Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.
