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Tomtit [17]
3 years ago
8

Which transformation will always map a onto itself? A. A 90 degree rotation about its center. B. A reflection across one of its

diagonals. C. a 180 degree rotation about its center. D. a reflection across a line joining the midpoints of opposite sides
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

i believe that the answer to that is c

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What is the area of the sector shown in the picture
tatuchka [14]

Answer:

The area of the sector shown is 4.75 pi

Step-by-step explanation:

First we have to know what fraction of the total circle that part represents

for that we divide 45 ​​by 360

45/360 = 1/8

now we calculate the area of ​​the circle and divide it by 8

a = ( π * 6² ) / 8

a = ( π * 36 ) / 8

a = π * 4.75

a = 4.75 pi

7 0
3 years ago
How do the gcf and the lcm help you when multiplying and adding or subracting fractions
kari74 [83]
<h3>Explanation:</h3>

GCF: the greatest common factor of numerator and denominator is a factor that can be removed to reduce the fraction.

  <em>Example</em>

The numerator and denominator of 6/8 have GCF of 2:

  6/8 = (2·3)/(2·4)

The fraction can be reduced by canceling those factors.

  (2·3)/(2·4) = (2/2)·(3/4) = 1·(3/4) = 3/4

___

LCM: the least common multiple of the denominators is suitable as a common denominator. Addition and subtraction are easily performed on the numerators when the denominator is common.

  <em>Example</em>

The fractions 2/3 and 1/5 can be added using a common denominator of LCM(3, 5) = 15.

  2/3 + 1/5 = 10/15 + 3/15 = (10+3)/15 = 13/15

4 0
3 years ago
20 POINTS!!!
notka56 [123]

\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------

(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s

6 0
3 years ago
Read 2 more answers
Find the value of the expression.<br> c²b<br> for b = 5 and c = 3
kicyunya [14]

Answer:

45

Step-by-step explanation:

c^2*b

We know that c is 3, and b is 5, so we can substitute them in

3^2*5

Solve the exponent first

9*5

Multiply

45

7 0
3 years ago
Read 2 more answers
Consider the table representing an exponential function.
Gnesinka [82]

Answer: f(x) is just a fancy way of writing y in an equation

Step-by-step explanation:

Example: f(x)= 2x+4 is the same as y= 2x+4

8 0
3 years ago
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