If the fraction (352/x-10) is equivalent to -22, find the value of x.
1 answer:
Answer:
The value of x is -6
Step-by-step explanation:
Let us equate the fraction by its equivalent
∵ = -22
→ Multiply both sides by (x - 10) to cancel the denominator of the left side
∴ × (x - 10) = -22 × (x - 10)
∴ 352 = -22(x - 10)
→ Simplify the right side by multiplying -22 by the bracket (x - 10)
∵ 352 = -22(x) - 22(-10)
∴ 352 = -22x + 220
→ Add 22x to both sides
∵ 22x + 352 = -22x + 22x + 220
∴ 22x + 352 = 220
→ Subtract 352 from both sides
∴ 22x + 352 - 352 = 220 - 352
∴ 22x = - 132
→ Divide both sides by 22 to find x
∴
∴ x = -6
∴ The value of x is -6
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simplifying a little bit,
looking for critical points,
We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.
When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.
Then apply your Zero-Factor Property,
and solve for x in each case to find your critical points.
Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.
Let's come back to this,
and take our second derivative.
Looking for inflection points,
Again, pulling out the smaller power of x, and fractional part,
And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.
Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.