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s2008m [1.1K]
3 years ago
5

For what value of the variable : is the value of 9-y twice as much as the value of y?

Mathematics
2 answers:
Sindrei [870]3 years ago
6 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

y = 3

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{"The value of 9-y twice as much as the value of y" can be written as:}}\\\\9-y = 2y

⸻⸻⸻⸻

\boxed{\text{Solving for 'y'...}}\\\\9-y=2y\\------------\\\rightarrow 9 -y + y = 2y + y\\\\\rightarrow 9 = 3y\\\\\rightarrow \frac{9=3y}{3}\\\\\rightarrow 3 = y\\\\\rightarrow \boxed{y = 3}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

jolli1 [7]3 years ago
5 0
Y=3 because 9-3=6 and 3*3=6
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Mr. Dunbar takes his wife out to dinner at Macados to celebrate the holidays. Their total bill was $48.36 but he had a coupon to
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Answer:

$51.38 or $60.45

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2 years ago
Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)
raketka [301]
<h3>Answer is   -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

g(x) = -3x

g(3) = -3*3

g(3) = -9

-------

alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) )  = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

7 0
3 years ago
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