A rectangle has a length of 11 meters less than 10 times its width. If the area of the rectangle is 9888 square meters, find the
length of the rectangle.
1 answer:
Step-by-step explanation:
The Length ,
L
=
284
f
t
.
Explanation:
Given:
Rectangle
Area,
A
=
8804
f
t
2
let W bet he width of the rectangle
L be the length of the rectangle
L
=
10
W
−
26
E
q
u
a
t
i
o
n
1
substitute to
e
q
u
a
t
i
o
n
2
A
=
(
L
)
(
W
)
e
q
u
a
t
i
o
n
2
A
=
(
10
W
−
26
)
(
W
)
8804
=
(
10
W
−
26
)
(
W
)
factor
8804
=
2
(
5
W
−
13
)
(
W
)
divide both sides by 2
4402
=
(
5
W
−
13
)
(
W
)
4402
=
5
W
2
−
13
W
transposing 4402 to the right side of the equation
0
=
5
W
2
−
13
W
−
4402
by quadratic formula
W
=
−
(
−
13
)
+
√
(
−
13
)
2
−
4
(
5
)
(
−
4402
)
2
(
5
)
W
=
[
13
+
√
169
+
88040
]
10
W
=
13
+
(
√
88209
)
10
W
=
13
+
297
10
W
=
310
10
W
=
31
ft
Thus ,
L
=
10
W
−
26
=
10
(
31
)
−
26
L
=
284
f
t
.
answer
W
=
−
(
−
13
)
−
√
−
(
−
13
2
)
−
4
(
5
)
(
−
4402
)
2
(
5
)
this is discarded since this will yield a negative
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A=a+b/2·h=9+4/2·3.5=22.75
Hoped I helped!
Answer:
The point of intersection between the 2 graphs.
Answer:
Step-by-step explanation:
To find equivalent fractions, multiply the numerator and the denominator by the same table.
a) 5/6
b) 7/11
c)9/7
Answer:
169
Step-by-step explanation:
13x13=169 in a square all sides are equal
Answer:
the top one, (-1,3)
Step-by-step explanation:
