It will have 2 solutions! this is because a negative and a negative cancel each other out and will make a positive under the radical.
Answers:
So the solution is (x,y) = (4, -1)
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Work Shown:
6x + 7y = 17
6x + 7( y ) = 17
6x + 7( -3x+11 ) = 17 ... replace every copy of y with -3x+11
6x - 21x + 77 = 17
-15x = 17-77
-15x = -60
x = -60/(-15)
x = 4
We'll use this x value to find y
y = -3x+11
y = -3(4)+11 ... replace x with 4
y = -12+11
y = -1
We have x = 4 and y = -1 pair up together to give us the solution (x,y) = (4, -1)
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To check the solution, we plug x = 4 and y = -1 into each equation
Plugging the values into the first equation leads to...
y = -3x+11
-1 = -3(4)+11
-1 = -1
This is effectively already done in the last part of the previous section. But it doesn't hurt to verify like this regardless.
We'll need to verify the second equation as well.
6x + 7y = 17
6(4) + 7(-1) = 17
24 - 7 = 17
17 = 17
We get a true equation, so the solution is confirmed with both equations. Overall, the solution to the system of equations is confirmed. This system is independent and consistent.
Answer:
6
Step-by-step explanation:
Answer:
$ 31050
Step-by-step explanation:
<em>Step 1 : Write the formula for calculating simple interest.</em>
Simple Interest = <u>P x R x T </u>
100
P: Principal Amount-The loan taken (30,000)
R: Interest rate at which the loan is give (6)
T: Time period of the loan in years-there are 12 months in 1 year. There are 7 months from May till June (7/12)
<em>Step 2: Substitute values in the formula</em>
Simple Interest = <u>30,000 x 6 x 7/12</u>
100
Simple Interest = $1050
<em>Step 3: Calculate the amount due at maturity</em>
At the maturity or the end of the time period given, the original or principal amount of the loan has to be repaid along with the simple interest.
Amount at maturity = Principal Amount + Simple Interet
Amount at maturity = 30,000 + 1050
Amount at maturity = $31050
!!
Dependent and independent variables. ... The dependent variables represent the output or outcome whose variation is being studied. The independent variables, also known in a statistical context as regressors, represent inputs or causes, that is, potential reasons for variation.
An independent variable is a variable that is manipulated to determine the value of a dependent variable s. The dependent variable is what is being measured in an experiment or evaluated in a mathematical equation and the independent variables are the inputs to that measurement.
I hope this helps you out
