Note: 6 employees means half of the employees contributed $7.75 each.
6 x $7.75 = $46.50.
To find how much money remains to be collected, subtract $46.50 from $100.
So, $100 - $46.50 = $53.50 is the answer.
For the experiment, you need 2L of cola. Your first option would be to purchase 1 2L bottle of cola for $2.25.
To calculate the second option, let's convert milliliters to liters first. There are 1,000 milliliters in 1 liter. With this, we know that there are 2,000 milliliters in 2 liters. Option 2 comes in 500-milliliter cans, which means that you would need 4 of them (2,000/500 = 4). 4 cans multiplied by $0.50 would cost you $2.00.
Let's check the cost of your answer options.
A. 4 cans - As seen above, this would cost $2.00.
B. 1 bottle - From the question, we know this would cost $2.25.
C. 2 bottles - This would be more soda than you need and would cost $4.50 ($2.25x2)
D. 1 can - This would be .5L and not enough soda for the experiment.
E. 5 cans - This would cost $2.50, but would be an extra 500mL of soda.
F. 2 cans - This would only be 1L of soda and not enough for the experiment.
G. 3 cans - This would be 1.5L of soda and not enough for the experiment either.
For the best price option, you would choose A (four cans of soda). This would give you the amount of soda that you need at the lowest price.
Answer:
Step-by-step explanation:
mean = total / amount of numbers
= 15/5 = 3
median = 4 middle number
mode = most common numbers = 3,2
Answer:
<em>It will occur zero times between midnight and one o'clock.</em>
Step-by-step explanation:
<u>Least Common Multiple (LCM)</u>
Three events keep James from sleeping: his clock ticking every 20 seconds, a tap dripping every 15 seconds, and his dog snoring every 27 seconds.
All three events happened together at midnight. They will happen together again the first time the numbers 20, 15, and 27 have a common multiple. This is the LCM.
List the prime factors of each number:
20: 2,2,5
15: 3,5
27: 3,3,3
Now multiply all the factors the maximum number of times they appear:
LCM=2*2*3*3*3*5=540
(a) All the events will happen together again after 540 minutes.
(b) Since 540 minutes = 9 hours, this event won't happen again until 9 am. Thus, it will occur zero times between midnight and one o'clock.
