Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer: Choice A) Triangle ABC is similar to triangle ACD by AA
AA stands for Angle Angle. Specifically it means we need 2 pairs of congruent angles between the two triangles in order to prove the triangles similar. Your book might write "AA similarity" instead of simply "AA".
For triangles ABC and ACD, we have the first pair of angles being A = A (angle A shows up twice each in the first slot). The second pair of congruent angles would be the right angles for triangle ABC and ACD, which are angles C and D respectively.
We can't use AAS because we don't know any information about the sides of the triangle.
Answer:
m∠A = 59°
Step-by-step explanation:
Supplementary angles mean that, when the two are combined, their total measurement will equal 180°.
It is given that one of the angles is 121°. Subtract 121 from 180:
180 - 121 = 59
m∠A = 59°
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A rectangle has 2 triangle
∴ 25 feet² × 2 = 50 feet²
1. linear equation
2. rearrange the equation so 4y = 12 - 3× and then divide both sides by 4 to get:
y = 3 - 3/4×
3. equation of a straight line / linear equation
4. gradient is + 3
5. not sure sorry
6. 3x = 12 - 4y. Divide each side by 3 to get:
x = 4 - 4/3y
7. use y = 3 - 3/4x by doing and x and y table. So when x = 1, y = 3 - 3/4 (1) (replace the x which the x value you've chosen). Then plot.
8. Make up any problem such as weather, food, etc.
Hope that helps !
