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Anni [7]
2 years ago
15

Find the product of 3/5 x 7/4. Then, write another pair of factors with the same product

Mathematics
2 answers:
dezoksy [38]2 years ago
7 0

Answer:

The product is 1.05

another pair of factors with the same product are 6/10 x 14/8

Aleksandr-060686 [28]2 years ago
5 0
3/5x7/4= 21/20 and srry I can't think of another factor with the sane product
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An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me
kirill115 [55]

Answer:

a) \lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

b) P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

c)  e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given \mu = 0.5 and we can solve for the parameter \lambda like this:

\frac{1}{\lambda} = 0.5

\lambda =2

So then X(t) \sim Poi (\lambda t)

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

\lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

P(X(2) >6)

And we can use the complement rule like this

P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

And we can solve this like this using the masss function:

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

T \sim Exp(\lambda=2)

The probability of no arrival during a period of duration t is given by:

f(T) = e^{-\lambda t}

And we want to find a value of t who satisfy this:

e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

3 0
3 years ago
Can someone please help me with this math problem:)
Dennis_Churaev [7]

Answer:

x = 20

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{x}{12} = \frac{15}{9} ( cross- multiply )

9x = 180 ( divide both sides by 9 )

x = 20

5 0
3 years ago
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Adante begins to evaluate the expression 3 1/3 x 5 1/4 using the steps below
il63 [147K]

Answer:

\frac{35}{2}

Step-by-step explanation:

To solve this problem we need to write the mixed fraction as a fractional number, as follows:

3 1/3 = 3 + \frac{1}{3} = \frac{9+1}{3} = \frac{10}{3}

5 1/4 = 5 + \frac{1}{4} = \frac{20+1}{4} = \frac{21}{4}

Then, evaluating the expression:

\frac{10}{3}×\frac{21}{4} = \frac{210}{12} =  \frac{35}{2}

4 0
3 years ago
It rained 2.79 inches in july. what was the average daily rainfall in july
Murrr4er [49]
Theres not enough information to properly answer this.

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3 years ago
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You think that $39,500 is a good salary and are interested in a job with Fast Pax. What other information might you want to know
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It is best to know whether the Fast Pax $39,500 salary is a gross salary or a net salary to make sure the amount you will get by working there. A net salary is a total amount of salary and benefits that you will get by working in a company and A gross salary is the amount of the salary only excluding the other benefits. These terms are important for employees to consider
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