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Nutka1998 [239]
3 years ago
6

The Kyoto Protocol was signed in 1997, and required countries to start reducing their carbon emissions. The protocol became enfo

rceable in February 2005. In 2004, the mean CO2 emission was 4.87 metric tons per capita. Is there enough evidence to show that the mean CO2 emission is lower in 2010 than in 2004? State the type I and type II errors in this case, consequences of each error type for this situation from the perspective of the agency overseeing the protocol, and the appropriate alpha level to use. State why you picked this alpha level.
Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:

Step-by-step explanation: Type 1 error is the error of rejecting a true null hypothesis or giving a false positive conclusion while type 11 error is the non rejection of a false null hypothesis.

The type 1 error for this question is: The mean CO2 is lower in 2010 than in 2004. While the type 11 error is:The mean C02 is higher in 2010 than In 2004. The consequences of making a type 1 error is that it will lead to a misguided information, while the consequences of making a type 11 error is that it could lead to loss of lives . The appropriate alpha level to use is 0.01, the reason is because the level of confidence needs to be high when it comes to health issues.

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Pavlova-9 [17]

Answer:

the answer is B

Step-by-step explanation:

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2 years ago
When testing for current in a cable with eleven color-coded wires, the author used
ddd [48]
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The number of test required is: 55

Explanation:

Using combination formula:

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= 55
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3 years ago
BRAINLIEST TO CORRECT QUICKLY
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Answer:

6 and 3 over 4 is greater than -3 and 1 over 4

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6 0
3 years ago
Read 2 more answers
Will award Brainlyest!!! Choose the equation that represents a line that passes through points (−3, 2) and (2, 1).
Pachacha [2.7K]

Answer:2. Rate of change, or slope, is the change in y over change in x. Remember that a point is given in (x, y). Also that you need two points to find the change.

If you have two points, (x1, y1) and (x2, y2), the rate of change or slope

In your problem, the given points are (0, -1) and (2, -11)

The "initial value" is the y-intercept - where the graph intersects the y-axis and also where x = 0. The given point (0, -1) has x = 0, so the initial value is -1.

4. Remember the model equation for a graph of a line is

y = mx + b,

where m is slope and b is y-intercept - where the graph intersects the y-axis and also where x = 0.

The x-axis of the graph would be number of weeks, since it is independent.

The y-axis of the graph would be how much money she has.

Since she starts (at 0 weeks) at $25, the first point would be (0, 25). Notice here that it is the y-intercept since x = 0. The value of b in the model equation of a line y = mx + b would be 25.

The rate of change, or slope, is $5/week. This is m in the model equation of a line y = mx + b.

Putting b = 25 and m = 5 into the model equation y = mx + b (remember we use this equation because it works for all lines), the equation would be

y = 5x + 25.

4.

The slope of this will be -0.5degrees/hr, or just -0.5 if it is used as m in the 

y = mx+b equation. The slope is negative because it "decreases".

5. 

Plot each point and connect the dots. Remember the first number corresponds to the x-axis and the second to the y-axis.

For example in the table for x = -2 and y = -6, the point is (-2, -6), and from the origin (0,0) you go left 2 on the x-axis and down 6 to plot the point.

9.

I think you can do this if you can do #3, but now you have to find b by plugging in given values.

y = mx + b

y = 1212x + b

We can plug in the given point (3,1) to find b.

1 = 1212(3) + b

b = -3625

y = 1212 - 3625

10. Don't know which function you are referring to.

The slope is $10/week, or m = 10.

A point is (4, 90) because "After 4 weeks, Roberta has $90."

The y-intercept is 50 because x (weeks) = 0 at that time.

y = mx + b

y = 10x + 50

8 0
2 years ago
Read 2 more answers
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