Answer:
(1)
And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:


And replacing we got:

And the width for this case would be 15.8 in
Step-by-step explanation:
For this case we know that the photo is rectangular. Let's define:
x = the width, y= the length
And we know that the perimeter is given by:
(1)
And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:


And replacing we got:

And the width for this case would be 15.8 in
Substituting the values given, we get
(2)*(3) + 4 ;
Using BODMAS
We get
6 + 4
= 10
Answer:
18:81 12:54
Step-by-step explanation:
The independent variable is x
y is dependent on the value of x