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Orlov [11]
3 years ago
10

HELP ME!!!!!!!!!!! Its the one in the middle

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

\frac{x3(p+5)}{10p(p-1)}

Step-by-step explanation:

BRAINLIEST PLEASE

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Justin has a credit card with a limit of $1,000 and an introductory APR of 0% for six months. After that the, APR for purchases
yuradex [85]
Given:
APR for first six months = 0%
APR for purchases after the 1st six months = 22.9%
APR for cash advances = 24.9%
APR for penalties = 29.4%

Obtaining $350 from an ATM using his credit card is a form of Cash Advances. So, the APR for this transaction is 24.9% Choice A.
4 0
3 years ago
Which functions are symmetric with respect to the origin?
Damm [24]

Answer:

The correct option is;

y = arcsinx and y = arctanx

Step-by-step explanation:

The given options are;

1) y = arcsinx and y = arccosx

Here, we have at the origin, where x = 0,  arccosx ≈ 1.57 while arcsinx = 0

Therefore arccosx does not intersect arcsinx at the origin for it to be symmetrical to arcsinx or the origin

2)  y = arccosxy and y = arctanx

Here arctanx = 0 when x = 0 and arcos x = 1.57 when x = 0 therefore, they are not symmetrical

3) y = arctanx and y = arccotx

Similarly, At x = 0, arccotx = 1.57 therefore, they are not symmetrical

4) y = arcsinx and y = arctanx

Both functions arcsinx and arctanx pass through the origin and their shapes are similar but inverted as they go from negative to positive.

3 0
3 years ago
Complete the equation and tell which property you used (18x2)x5=18x(2x____)
tangare [24]
<span>Associative Property.
(18x2)x5=18x(2x5)
All you have to do is move the parentheses but keep the numbers the same.</span>
4 0
3 years ago
A box of golf balls costs $7.32. At that rate, how much will a box of 15 balls cost?
san4es73 [151]
Your question is vague. There is not enough information. How many balls are in the box? 15 boxes would cost 109.80 thought.
3 0
3 years ago
Can the polynomial equation have exactly 1 real solution, including any repeated solutions? (Use the Fundamental Theorem of Alge
Kryger [21]

yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy

-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)

9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)

5 0
3 years ago
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