Answer:
1.) One sample t test
2.) New steroid does not decrease blood glucose level in rats ; H0 : μ = 31
3.) New steroid does blood glucose level in rats ; H1 : μ ≠ 31
4.) 2.718
5.) 3.36
Step-by-step explanation:
We only have one sample; hence, we use an independent sample t test.
Given the sample data :
X : 35,36,37,33,34,35,33,35,37,36,34,35
Using calculator;
Sample mean, Xbar = 35
Null hypothesis ;supports that the mean glucose level of species equals ; H0 : μ = 31
The alternative hypothesis ; H1 negates the null hypothesis and aligns with the sample mean ; 35 > 31 ;
H1 : μ > 31
The critical value can be obtained from the T-distribution table ;
α = 0.01 ; degree of freedom, df = n - 1 = 12 - 1 = 11
Tcritical value = 2.718
Tstatistic : (xbar - μ) ÷ (s/√n)
Tstatistic = (35 - 31) ÷ (4.12/√12)
Tstatistic = 3.36
Tstatistic is more extreme Than the critical value
