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bonufazy [111]
3 years ago
5

You are working with a quadratic equation and construct the following table.

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

a) Vertex is at (-3, -1)

b) y-intercept is at (0,8)

c) x intercept is at (-4,0) and (-2,0)

d) x=-3

Step-by-step explanation:

We know the vertex is the lowest or highest part of a parabola meaning all the points are reflected across.  It is the only y value without a matching pair

E.x. -1 and 1, -3 and 3

The only point without a corresponding y value is (-3,-1) therefore the vertex is at (-3,-1)

The y-intercept is where the parabola meets the y axis or the x value is equal to 0, we just have to find when x = 0 to find the y intercept

y intercept: (0,8)

For the x intercept's it is just the reverse, you need to find where the parabola crosses the x axis or when y = 0

x intercept 1:(-4,0)

x intercept 2: (-2,0)

The axis of symmetry is also the x coordinate of the vertex which is 3 so

x = 3

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3 years ago
What is the solution of the following question?<br> x^2+10x+25=12
zalisa [80]
Make equal to 0
minus 12from both sides
x^2+10x+13=0
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x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
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aprox
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3 0
2 years ago
Read 2 more answers
Hi, can you help me answer this question, please, thank you!
frutty [35]

Given:

mean, u = 0

standard deviation σ = 1

Let's determine the following:

(a) Probability of an outcome that is more than -1.26.

Here, we are to find: P(x > -1.26).

Apply the formula:

z=\frac{x^{\prime}-u}{\sigma}

Thus, we have:

\begin{gathered} P(x>-1.26)=\frac{-1.26-0}{1} \\  \\ P(x>-1.26)=\frac{-1.26}{1}=-1.26 \end{gathered}

Using the standard normal table, we have:

NORMSDIST(-1.26) = 0.1038

Therefore, the probability of an outcome that is more than -1.26 is 0.1038

(b) Probability of an outcome that

4 0
1 year ago
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