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2 years ago

I think its the second one but I'm not sure..

Mathematics

1 answer:

yuradex [85]2 years ago

7 0

Yes it’s correct. You just need to plug each of the x and y values to see if they satisfy the equation.

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Help me out please I don’t understand?

zepelin [54]

Answer:

ya i dont either

Step-by-step explanation:

6 0

2 years ago

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

2 years ago

Four artists open a business selling paintings and agree to split the profits equally. They spent $150 on supplies. If their tot

pashok25 [27]

First, I would subtract 150 from 870. You get 720. Then I would divide that equally among the four artists. 720/4=180. So each person's share is $180.

8 0

2 years ago

Read 2 more answers

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a m

Stells [14]

Answer: See explanation

Step-by-step explanation:

Here is the complete question:

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.

A. Students: 72

Minimum of chaperones: 9

B. Students: 16

Minimum of chaperones: 2

C. Students: 60

Minimum of chaperones: 6

D. Students: 45

Minimum of chaperones: 5

E. Students: 40

Minimum of chaperones: 8

Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.

We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:

Students: 72

Minimum of chaperones: 9

This will be: 72/9 = 8

Therefore, this is correct.

B. Students: 16

Minimum of chaperones: 2

This will be: 16/2 = 8

This is correct

C. Students: 60

Minimum of chaperones: 6

This will be: = 60/6 = 10.

Therefore, this is wrong

D. Students: 45

Minimum of chaperones: 5

This will be 45/5 = 9

Therefore, this is wrong.

E. Students: 40

Minimum of chaperones: 8

This will be: 40/5 = 8.

Therefore, this is wrong.

Therefore, options A and B are correct.

3 0

2 years ago

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The bar diagram represents 24 hours in one day and shows a mark at 30%. If you sleep 30% of the day, how many hours do you sleep

yan [13]

Answer:

24 hr × 30% = 24 hr × 0.30 = 7.2 hr (or 7 hr 12 min)

6 0

3 years ago

Read 2 more answers