Answer:
1 N
Explanation:
From coulomb's law,
The force of attraction between two charges is inversely proportional to the square of the distance between the charges.
From the question,
Assuming the charges are the same in both case,
F ∝ /r²....................... Equation 1
Fr² = k
F'r'² = Fr²........................... Equation 2
Where F' = First Force, r'² = First distance, F = second force, r² = second distance.
make F the subject of the equation,
F = F'r'²/r².................... Equation 3
Given: F' = 4 N, r' = 3 m, r = 6 m
Substitute into equation 3
F = 4(3²)/6²
F = 36/36
F = 1 N
So the equation used in this problem is ΔX=V0*T+1/2AT^2 the X is the distance, v0 is initial velocity, T is time, and a is acceleration. So when we plug these values it we get: 108= 0•T+1/2•3•T^2,the 0•t disappears, and the 1/2•3 gets us 1.5, so we have 108=1.5T^2, then we divide 108 by 1.5 which gets us 72=t^2, and we then take the square root and get 8.49=T so the answer is 8.49 seconds.
Answer:
11.6532 x 10⁻¹¹ J or 7.3 MeV is given off
Explanation:
Mass of an alpha particle = 4.0026u, ∴ mass of three = 12.0078u
Find the difference in mass.
Mass of three alpha - Mass of Carbon nucleus
12.0078u - 12u = 0.0078u
Since 1u = 1.66 x 10⁻²⁷ kg
Therefore, 0.0078u = 1.2948 x 10⁻²⁷
Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²
Formular for Energy ==> E₀ = mc²
E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²
E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J
E = 11.6532 x 10⁻¹¹ J
Or, if you need your energy in MeV
1 MeV = 1.60x10⁻¹³ J
Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J
It will give you 7.3 MeV
