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Natalija [7]
2 years ago
6

A circular rod with a gage length of 3.5 mm and a diameter of 2.8 cmcm is subjected to an axial load of 68 kN . If the modulus o

f elasticity is 200 GPa, what is the change in length?
Physics
1 answer:
Crank2 years ago
7 0

To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

\delta = \frac{PL}{AE}

Where,

P = Axial Load

l = Gage length

A = Cross-sectional Area

E = Modulus of Elasticity

Our values are given as,

l = 3.5m

D = 0.028m

P = 68*10^3 N

E = 200GPa  

A = \frac{\pi}{4}(0.028)^2 \rightarrow 0.0006157m^2

Replacing we have,

\delta = \frac{PL}{AE}

\delta = \frac{( 68*10^3)(3.5)}{(0.0006157)(200*10^9)}

\delta = 0.001932m

\delta = 1.93mm

Therefore the change in length is 1.93mm

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mylen [45]

Answer:

The impulse is  I  =  153.8 \ N \cdot s

The opponents velocity is  v=  1.33 m/s

The opponents head recoils velocity  v_r = 30.8 \ m/s

Explanation:

From the question we are told that

    The force of the blow is  F=  1025 \ N

    The duration of the blow is  t =  0.150

      The mass of the opponent is  m_o  =  116 \ kg

       The mass of the opponents head is  m_h  = 5 \ kg

The impulse the boxer imparts is mathematically represented as

         I  =  F *  t

substituting values

         I  =  1025 * 0.150

          I  =  153.8 \ N \cdot s

The impulse can also be mathematically evaluated as

         I  =  m_o * v

substituting values

          153.8  =  116 * v

          v=  \frac{153.8}{116}

          v=  1.33 m/s

The recoil velocity is mathematically represented as  

              v_r =  \frac{I}{m_h}

substituting values

                v_r =  \frac{153.8}{5}

                v_r = 30.8 \ m/s

5 0
3 years ago
The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2
Oliga [24]

Answer:

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2 in front of water and 1 in front of oxygen

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V2O5 + 5CaS → 5CaO + V2S5

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Which lists the numbers of each atom the other half of the equation would contain?

3 Mg, 2 P, 14 O, 12 H

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How much of substance AB would Colin make?

55g

Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting equation?

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Which best describes the law of conservation of mass?

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6 0
2 years ago
Read 2 more answers
1 pc
nlexa [21]

Answer:

A spectroscope

Explanation:

A spectroscope is used by scientists to separate a source of light ( usually white light ) into its various compositions. i.e it is used to determine the chemical makeup of a visible source of light. hence to determine whether the red light produces photo electrons, which is a chemical makeup of visible light a spectroscope should be added to the circuit.

photo electrons are electrons emitted/ejected from a surface usually metallic surface in the form of a photoelectric effect  when a source of light is shines on the surface

6 0
3 years ago
Consider the following geometric solids.
Bad White [126]

Before answering this question, first we have to understand the effect of ratio of surface area to volume on the rate of diffusion.

The rate of diffusion for a body having larger surface area as compared to the ratio of surface area to volume will be more than a body having less surface area. Mathematically it can written as-

                           V∝ R            [ where v is the rate of diffusion and r is the ratio of surface area to volume]

As per the question,the ratio of surface area to volume for a sphere is given 0.08m^{-1}

The surface area to volume ratio for right circular cylinder is given 2.1m^{-1}

Hence, it is obvious that the ratio is more for right circular cylinder.As the rate diffusion is directly proportional to the surface area to volume ratio,hence rate of diffusion will be more for right circular cylinder.

Hence the correct option is B. The rate of diffusion would be faster for the right cylinder.


5 0
2 years ago
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Find the intensity of a 55 dB sound given I 0=10^-12W/m^2
MakcuM [25]

Answer:

3.16 × 10^{-7} W/m^{2}

Explanation:

β(dB)=10 × log_{10}(\frac{I}{I_{0} })

I_{0}=10^{-12} W/m^{2}

β=55 dB

Therefore plugging into the equation the values,

55=10 log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

5.5= log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

10^{5.5}= \frac{I}{10^{-12} }

316227.76×10^{-12}= I

I= 3.16 × 10^{-7} W/m^{2}

5 0
2 years ago
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