All categories

2 years ago

What is quivalent to 5/8?

Mathematics

2 answers:

coldgirl [10]2 years ago

7 0

Answer:

10/16 is also equivalent

Nadusha1986 [10]2 years ago

4 0

Answer:

0.625

Step-by-step explanation:

All you have to do is put it in decimal form.

You might be interested in

Evaluate the expression. 8^7/8^7

Karo-lina-s [1.5K]

The expression is equal to one. Because a number over the same number is equal to one. I think that is the answer.

Hope this helps!

3 0

4 years ago

HELP PLZZZZZ !!!!!!!! I DON'T UNDERSTAND

denis23 [38]

Answer:

Step-by-step explanation:

As seen below, the equation of a circle is (x - h)^2 + (y - k)2 = r^2.

In this case, h = the x-value of the center of the circle, which is -2, and k = the y-value of the center of the circle, which is 3. The radius r is 4.

(x - (-2))^2 + (y - (3))^2 = (4)^2

(x + 2)^2 + (y - 3)^2 = 16

This corresponds to answer choice C.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Which relation describes a function?

Kisachek [45]

Answer:

{(-2, -3), (-3, -2), (2,3), (3, 2)}

Step-by-step explanation:

A function is a set of ordered pairs in which no two pairs have the same first number.

In other words, an x cannot be paired with two y's.

A function takes an x and pairs it with one and only one y.

{(0,0), (0, 2), (2.0), (2, 2)} is not a function because it pairs 0 with both 0 and 2.

{(2,-1), (2, 1), (3,-1), (3, 1)} is not a function because it pairs 2 with both -1 and 1.

{(2, 2), (2, 3), (3, 2), (3, 3)} is not a function because it pairs 2 with both 2 and 3.

8 0

4 years ago

Read 2 more answers

Find x: a - bx = cx + d

V125BC [204]

Answer:

x= -(d-a)/(b+c)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero

5 0

3 years ago

Find K by evaluating Limit

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

$\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4$

{L'Hospital's rule}

I hope this helps you

:)

6 0

2 years ago