What happens as the key length increases in an encryption application?

1 answer:

6 0

<span>The answer is : Increasing the key length of DES would protect it against brute force attacks. </span>Brute force is when the attacker tries every key knowing that one will eventually work. <span>Key length increase proportionally increases the key space, having a keyspace l</span>arge enough that it takes too much time and money to accomplish a brute force attack.

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a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d

BaLLatris [955]

Answer:

$\frac{10!}{2}mins$

Explanation:

12 seconds to try one combination will be equivalent to $\frac{1}{12}\times 60 = \frac{1}{5} \ mins$

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to $\frac{10!}{2}$ .

Total number of passwords combination possible for each position in 9 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to $\frac{10!}{1}$ .

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1. Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by $\frac{1}{5} \ mins$ to get the total number of time needed to guarantee access to database = $[\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}$

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By choosing to implement an open office layout, greater communication between the supervisor and computer programmers would occur compared to when they were separated.

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32-bit is the correct answer to this question.

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Alexa says minus 8

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