Answer:
Additive Identity I think, I'm not sure
Step-by-step explanation:
Tell me in the comments if I'm wrong.
g(a)=33a−2; Find g(1)
g(1) means the value of a is 1. Replace a in the equation with 1 and solve.
33(1) - 2 = 33-2 = 31
g(1) = 31
You mix the letters m,a,t,h,e,m,a,t,i,c,a and l thoroughly without looking you draw one letter probability p(A) . write the prob
erastovalidia [21]
There are 12 total letters, of which 3 are A's.
This means you have a
probability of randomly selecting an A.
First solve for g(1)
Plug in 1 for the equation g(x)
g(1) = -(1) + 4
g(1) = 3
Now plug 3 in for f(x)
f(3) = 3(3)^2 + 4(3) + 1
f(3) = 3(9) + 12 + 1
f(3) = 27 + 12 + 1
f(3) = 40
Solution: f(g(1)) = 40
