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Readme [11.4K]
3 years ago
8

A kitchen is 10ft long and 8ft wide.if kitchen floor tiles

Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

1536 tiles

Step-by-step explanation:

Given,

The length of kitchen = 10 ft,

Width of the kitchen = 8 ft,

∵ The shape of floor of kitchen must be rectangular,

Thus, the area of the kitchen = 10 × 8 = 80 square ft = 11520 in²

( Since, 1 square feet = 144 square inches )

Now, the length of a tile = 2.5 in and its width = 3 in,

So, the area of each tile = 2.5 × 3 = 7.5 in²,

Hence, the number of tiles needed = \frac{\text{Area of kitchen}}{\text{Area of each tile}}

=\frac{11520}{7.5}

= 1536

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The pattern 2, 5, 17, ________, ________ follows the rule multiply by 4, then subtract 3. What are the next two terms?
vitfil [10]

Answer:

None of the answer choices.

Step-by-step explanation:

The pattern to this problem is multiply by 4, and subtract 3. However when doing 17 * 4, you get 68. Look how both of the answer chouces start with 68, and we haven't even subtracted 3 yet. This shows that the answer choices are wrong.

<u>Correct Answer: 65, 257</u>

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Margaret is planning a rectangle garden. It's length is 4ft less than twice it's width. It's area is 170ft squared. What are the
Stolb23 [73]
L*W=Area L=2w-4

(2w-4)*w=170

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3 years ago
A wireless phone company determines that 12 out of every 350 Model A phones are returned because of a defective screen. If the c
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I think it would be 66
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Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees0° and standard deviation of 1.00d
nikitadnepr [17]

For this question, we assume that 2.5% of the thermometers are rejected at both sides of the distribution because they have readings that are too low or too high.

Answer:

The "two readings that are cutoff values separating the rejected thermometers from the others" are -1.96 Celsius degrees (below which 2.5% of the readings are too low) and 1.96 Celsius degrees (above which 2.5% of the readings are too high).

Step-by-step explanation:

We can solve this question using the <em>standard normal distribution</em>. This is a normal distribution with mean that equals 0, \\ \mu = 0, and standard deviation that equals 1, \\ \sigma = 1.

And because of using the <em>standard normal distribution</em>, we are going to take into account the following relevant concepts:

  • <em>Standardized scores or z-scores</em>, which we can consider as the <em>distance from the mean</em> in <em>standard deviations units</em>, and the formula for them is as follows:

\\ Z = \frac{X - \mu}{\sigma} [1]

A positive value indicates that the possible raw value X is <em>above</em> \\ \mu, and a negative that the possible raw value X is <em>below</em> the mean.

  • <em>The [cumulative] standard normal table:</em> there exists a table where all these values correspond to a probability, and we can apply it for every possible normally distributed data as well as we first standardize the possible raw values for <em>X</em> using [1]. This table is called the <em>standard normal table</em>, and it is available in all Statistics books or on the Internet.

From the question, we have the following information about the readings on the thermometers, which is a normally distributed random variable:

  • Its <em>mean</em>, \\ \mu = 0 Celsius degrees.
  • Its <em>standard deviation</em>, \\ \sigma = 1.00 Celsius degrees.

It coincides with the <em>parameters</em> of the <em>standard normal distribution</em>, and we can find probabilities accordingly.

It is important to mention that the readings that are too low or too high in the normal distribution are at both extremes of it, one of them with values below the mean, \\ \mu, and the other with values above it.

In this case, we need to find:

  • First, the value <em>below</em> which is 2.5% of the lowest values of the distribution, and
  • Second, the value <em>above</em> which is 2.5% of the highest values of the distribution.

Here, we can take advantage of the <em>symmetry</em> of the normal or Gaussian distributions. In this case, the value for the 2.5% of the lowest and highest values is the <em>same in absolute value</em>, but one is negative (that one below the mean, \\ \mu) and the other is positive (that above the mean).

Solving the Question

<em>The value below (and above) which are the 2.5% of the lowest (the highest) values of the distribution</em>

Because \\ \mu = 0 and \\ \sigma = 1 (and the reasons above explained), we need to find a <em>z-score</em> with a corresponding probability of 2.5% or 0.025.

As we know that this value is below \\ \mu, it is negative (the z-score is negative). Then, we can consult the <em>standard normal table</em> and find the probability 0.025 that corresponds to this specific z-score.

For this, we first find the probability of 0.025 and then look at the first row and the first column of the table, and these values are (-0.06, -1.9), respectively. Therefore, the value for the z-score = -1.96, \\ z = -1.96.

As we said before, the distribution in the question has \\ \mu = 0 and \\ \sigma = 1, the same than the standard normal distribution (of course the units are in Celsius degrees in our case).

Thus, one of the cutoff value that separates the rejected thermometers is -1.96 Celsius degrees for that 2.5% of the thermometers rejected because they have readings that are <em>too low</em>.

And because of the <em>symmetry</em> of the normal distribution, <em>z = 1.96 is the other cutoff value</em>, that is, the other lecture is 1.96 Celsius degrees, but in this case for that 2.5% of the thermometers rejected because they have readings that are <em>too high</em>. That is, in the standard normal distribution, above z = 1.96, the probability is 0.025 or \\ P(z>1.96) = 0.025 because \\ P(z.

Remember that

\\ P(z>1.96) + P(z

\\ P(z>1.96) = 1 - P(z

\\ P(z>1.96) = 1 - 0.975

\\ P(z>1.96) = 0.025

Therefore, the "two readings that are cutoff values separating the rejected thermometers from the others" are -1.96 Celsius degrees and 1.96 Celsius degrees.

The below graph shows the areas that correspond to the values below -1.96 Celsius degrees (red) (2.5% or 0.025) and the values above 1.96 Celsius degrees (blue) (2.5% or 0.025).

4 0
3 years ago
What is the total volume of all four lockers if one side of a locker is two feet long
Vitek1552 [10]

Answer:

32

Step-by-step explanation:

If one side is 2 feet and it has 4 sides then 4 times 2 = 8

8 times 4 = 32

Hope this helps

5 0
2 years ago
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