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3 years ago

A kitchen is 10ft long and 8ft wide.if kitchen floor tiles

Mathematics

1 answer:

Vilka [71]3 years ago

7 0

Answer:

1536 tiles

Step-by-step explanation:

Given,

The length of kitchen = 10 ft,

Width of the kitchen = 8 ft,

∵ The shape of floor of kitchen must be rectangular,

Thus, the area of the kitchen = 10 × 8 = 80 square ft = 11520 in²

( Since, 1 square feet = 144 square inches )

Now, the length of a tile = 2.5 in and its width = 3 in,

So, the area of each tile = 2.5 × 3 = 7.5 in²,

Hence, the number of tiles needed = $\frac{\text{Area of kitchen}}{\text{Area of each tile}}$

$=\frac{11520}{7.5}$

= 1536

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At haley's bakery over the course of a year she sold 81 birthday cakes for $66 a cake. At the end of the year she determined tha

svetlana [45]

Answer:

=594

Step-by-step explanation:

(81)(66)(1)

=594

4 0

3 years ago

Kolby decided he wanted to go to the amusement park. The amusement park charges $8.00 for entry and $1.40 for each ride.

Dmitry_Shevchenko [17]

Answer:

Part A:

1.40x+8.00=C

Part B:

1.40x+8=26

-8 -8

1.40x=18

/1.40 /1.40

x=11 total rides

Step-by-step explanation:

An expression to represent this would be 1.40x+8.00=C (C is total cost).

If you had $26.00 you would first spend $8.00 on the entry leaving you with $18.00. Then you would divide the $18 by $1.40 for each ride to get 12.8... It doesn't make sense to go on a fraction of a ride so you just round down to 11 rides

8 0

2 years ago

Each side of a square is increasing at a rate of 6cm/s. At what rate is the area of the square increasing when the area of the s

diamong [38]

Area of a square = length²
A = x²
16 = x²; x = 4
dA/dx = 2x cm²/s
dx/dt = 6 cm/s
Using chain rule:
dA/dt = dA/dx * dx/dt
dA/dt = 2x * 6
dA/dt = 12x
At x = 4,
dA/dt = 12(4) = 48 cm²/s

7 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

2. The Martian Zoological Society has a unique display of the native monocephalous fauna:

german

Answer:

There are 12 pentapods and 8 Tripods, which in total add up to 84 feet.

Step-by-step explanation:

Given that both the Tripods and the Pentapods have, at least, 3 feet (the Pentapods have 5), and that in total between both groups they add 20 heads and 84 feet, the following logical reasoning can be made:

If there are 20 heads, there are 20 Martians in all. Each of them has, at least, 3 feet, with which in principle the 20 Martians would add up to a total of 60 feet (20 x 3). Therefore, there is a surplus of 24 feet (84 - 60).

If the Pentapods have 2 feet more than the Tripods, the number of Pentapods in the total Martians is determined by that difference. Thus, if there are 24 feet left, there are 12 Pentapods (24/2).

Therefore, in the group of Martians there are 12 pentapods (12 x 5 = 60) and 8 Tripods (8 x 3 = 24), which in total add up to 84 feet (60 + 24).

6 0

3 years ago