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EastWind [94]
3 years ago
10

Which equation shows y=−12x+4 is in standard form?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

-8x

Step-by-step explanation:

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1. The sides of a triangle have lengths of 5, 8, and 6.(1/ 2). An angle bisector meets the side of length 6.(1/ 2). Find the len
Advocard [28]

Answer:

Step-by-step explanation:

i assume x+y=6(1/2)=\frac{13}{2}

\frac{5}{8}=\frac{x}{y}=\frac{x}{\frac{13}{2}-x}=\frac{2x}{13-2x}\\65-10x=16x \\26 x=65\\2x=5\\x=\frac{5}{2}\\y=\frac{13}{2}-\frac{5}{2}=\frac{8}{2}=4

6 0
3 years ago
PUZZLE: six wolves catch six lambs in six minutes. How many wolves will be needed to catch sixty lambs in sixty minutes?
Korolek [52]
Six i think cause it take each wolf 6 minutes to catch a lamb so it should still be six
4 0
3 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
3 years ago
Which of the following sets of measurements could be the side lengths of a right triangle?
nordsb [41]
Would have to be C due to all the other numbers not adding up to be a right angle
3 0
3 years ago
Read 2 more answers
What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30​
tia_tia [17]

Answer:

16

Step-by-step explanation:

ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30

number of terms =13

median=[(n+1)/2] th term

=[(13+1)/2] th term

=[14/2] th tem

=7th term

=16

7 0
3 years ago
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