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3 years ago

Which of the binomials below is a factor of this trinomial?

Mathematics

2 answers:

Tamiku [17]3 years ago

8 0

None of those answers are correct sadly.

maks197457 [2]3 years ago

4 0

Answer:

x-14

Step-by-step explanation:

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Nancy was 59 7/8 inches tall at the end of summer.she was 62 1/8 inches by her birthday in March.how much did she grow during th

enyata [817]

Answer:

2 2/8 inches

Step-by-step explanation:

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3 years ago

PLEASE HELP— URGENT// MIDDLE SCHOOL MATHEMATICS

MaRussiya [10]

Answer:

Step-by-step explanation:

The new bike costs 180 dollars

Parents paid 40%

what is a percentage? per cent= divide by 100

parents paid 180 *40/100=180*0.4=72 dollars

Jennifer has to pay the rest

180-72=108

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3 years ago

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Complete the inequality.

Vitek1552 [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help me answer this question.

Alex787 [66]

1. Change x = 4t into x = 3t

$4t\cdot\frac{3}{4}=3t$ so

$y=(\frac{3}{4}t)^2-1=\frac{9}{16}t^2-1$

Answer A and D are wrong.

2. Change x = 4t into x = 2t

$4t\cdot\frac{1}{2}=2t$ and

$y=(\frac{1}{2}t)^2-1=\frac{t^2}{4}-1$

Answer b is correct.

3. Change x = 4t into x = 8t

$4t\cdot2=8t$ and

$y=(2t)^2-1=4t^2-1$

Answer C. is correct, E. is wrong.

7 0

3 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago