Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.
the formula for a combination is

where n is a total number of choices ( 11 )
and r is number chosen out of those choices (4)
so
C(11,4)= \frac{11!}{4!(11-4)!}
She has 330 possible choices to come home with 4 pieces of jewelry
The zeros of the function occur when the graph meet the x-axis so in this case the zeros occur at B ( 0 and 5)
Answer:
15
Step-by-step explanation:
To solve this, divide 192 by 8:
192/9 = 24
Subtract 9 from 24:
24 - 9 = 15
Therefore, 8 times the sum of 9 and 15 is 192