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ira [324]
2 years ago
8

A storage bin in the corner of joes room has the dimensions shown below

Mathematics
1 answer:
RoseWind [281]2 years ago
4 0

Answer:

4 i think


Step-by-step explanation:


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3 years ago
When the distributive property is used to solve the equation 5(2 + 4) = 32 - 5, what is the next step?
coldgirl [10]

Answer:

no solution

Step-by-step explanation:

5(2 + 4) = 32 - 5

Simplify

5×6=32−5

simplify

30=32−5

Simplify

30=27

There is no solution

3 0
3 years ago
The point (-4, -1), is the bottom of a triangle. Which point would it map to if the triangle was translated right 5 units and re
lyudmila [28]

Answer:

Step-by-step explanation:

(x,y)→(x+5,y)

(-4,-1)→(-4+5,-1)=(1,-1)

reflection about x-axis

(x,y)→(x,-y)

(1,-1)→(1,1)

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2 years ago
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5 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
2 years ago
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