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Inga [223]
3 years ago
9

Please help me answer this question.

Mathematics
1 answer:
Alex787 [66]3 years ago
7 0
1. Change x = 4t into x = 3t

4t\cdot\frac{3}{4}=3t so

y=(\frac{3}{4}t)^2-1=\frac{9}{16}t^2-1

Answer A and D are wrong.

2. Change x = 4t into x = 2t

4t\cdot\frac{1}{2}=2t and

y=(\frac{1}{2}t)^2-1=\frac{t^2}{4}-1

Answer b is correct.

3.  Change x = 4t into x = 8t

4t\cdot2=8t and

y=(2t)^2-1=4t^2-1

Answer C. is correct, E. is wrong.

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Do the data in the table represent a direct variation or inverse variation? Write an equation to model the data in the table?
notsponge [240]

Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x

<h3>Variation</h3>

  • Direct variation

y = k × x

4 = k × 2

4 = 2k

k = 4/2

k = 2

when y = 2 and x = 4

y = k × x

= 2 × 4

y = 8

  • Indirect variation

y = k/x

4 = k / 2

8 = k

when y = 2 and x = 4

y = k/x

2 = k/4

2 × 4 = k

k = 8

So,

y = k/x

y = 8/x

Learn more about variation:

brainly.com/question/6499629

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5 0
2 years ago
Find the quotient 9 3/5 divided 8/15
Whitepunk [10]
The answer is 81/8
Alternative Forms:
10 1/8 or 10.125
4 0
3 years ago
Peter invests £3000 for 2 years in a saving account. He was paid 3% per annum compound interest. How much did Peter have in his
madam [21]

Answer:

£3182.7

Step-by-step explanation:

£3000=100%

? =3%

3×3000/100

=£90

£(3000+90)=£3090(1st year)

£3090=100%

? =3%

3×3090/100=£3182.7

4 0
3 years ago
Which table contains only corresponding x - values and y - values where the value of y is 3 more than the quotient of x and 2?
melisa1 [442]

Fr like whats the answer choice

6 0
2 years ago
Read 2 more answers
Determine if (x+1) is a factor 4x^2 + 2x - 5Use synthetic division
ikadub [295]

Given

4x^2+2x-5

Divide it by (x+1) using synthetic division, as shown below

The green line is a minus sign.

Thus,

\Rightarrow4x^2+2x-5=(x+1)(4x-2)-3

Therefore, since the remainder is different than zero, (x+1) is not a factor of 4x^2+2x-5

6 0
1 year ago
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