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Xelga [282]
3 years ago
15

HELPPPPPPPPPPPPPPP MEEEEEEEEEE PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

Mathematics
1 answer:
grin007 [14]3 years ago
5 0
I would say d that what i got.
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Pleaseeee help asappppppp
lord [1]

Answer:

ED = 12

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7 0
2 years ago
Twice a number decreased by four is greater than ten, what numbers satisfy this condition
bezimeni [28]
The values are represented by the inequality x>7
6 0
3 years ago
Find the values of x and y that satisfy the equation –21 + 5yi = 7x – 10i.
kap26 [50]

Answer:

The values of x and y are x = -3 and y = -2

Step-by-step explanation:

In the complex numbers if a + bi = c + di, then the real parts are equal and the imaginary parts are equal

  • a = c
  • b = d

Let us use this rule to solve the question

∵ -21 + 5yi = 7x - 10i

∴ The real parts are -21 and 7x

∴ The imaginary parts are 5y and -10

∵ The real parts are equal

∴ 7x = -21

→ Divide both sides by 7

∴ \frac{7x}{7} = \frac{-21}{7}

∴ x = -3

∵ The imaginary parts are equal

∴ 5y = -10

→ Divide both sides by 5

∴ \frac{5y}{5} = \frac{-10}{5}

∴ y = -2

∴ The values of x and y are x = -3 and y = -2

8 0
3 years ago
I NEED AN ANSWER! ASAP! EXTRA POINTS PLEASE!!!
Margaret [11]

Histogram would be right

5 0
3 years ago
Read 2 more answers
Solve the equation in two different ways. Choose one method of solving in detail 5x+7(x+1) = 5x - 21
frozen [14]

Answer:

METHOD 1:

5x+7(x+1)=5x-21

5x+7x+7=5x-21

12x+7=5x-21

12x-5x=-21-7

7x=-28

x=28/7

x=4

METHOD 2:

5x+7(x+1)=5x-21

5x+7(x+1)=5x-21-5x

7(x+1)=-21

7x+7=-21

7x=-28

x=4

Step-by-step explanation:

METHOD 1:

5x+7(x+1)=5x-21

5x+7x+7=5x-21

12x+7=5x-21

12x-5x=-21-7

7x=-28

x=28/7

x=4

METHOD 2:

5x+7(x+1)=5x-21

5x+7(x+1)=5x-21-5x

7(x+1)=-21

7x+7=-21

7x=-28

x=4

6 0
3 years ago
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